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n200080 [17]
3 years ago
7

Quadrilateral ABCD is transformed to create A′B′C′D′. Match the coordinates of A′ with the transformations that create it.

Mathematics
1 answer:
bulgar [2K]3 years ago
6 0

Answer:

The answer is below

Step-by-step explanation:

From the image attached, the coordinates of point A is at (2, -4).

Transformation is the movement of a point from its initial location to a new position. Types of transformation include dilation, reflection, translation and rotation.

If a point A(x, y) is reflected over the x axis, the new point is at  A'(x, -y)

If a point A(x, y) is translated a units right and b units down, the new location is at A'(x + a, y - b)

If a point A(x, y) is dilated by  factor of a, the new location is at A'(ax, ay)

If a point A(x, y) is  rotated 180° clockwise about the origin, the new location is at A'(-x, -y)

Hence:

For Quadrilateral ABCD is reflected over the x-axis, the coordinates of A' is at A'(2, 4)

For Quadrilateral ABCD is translated 2 units right and 1 unit down, the coordinates of A' is at A'(4, -5)

For Quadrilateral ABCD is dilated by a scale factor of 3, the coordinates of A' is at A'(6, -12)

For Quadrilateral ABCD is rotated 180° clockwise about the origin the coordinates of A' is at A'(-2, 4).

Step-by-step explanation:

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Change the fraction w-3/w+5 into an equivalent fraction with the denominator w2 + w – 20.
viktelen [127]
ANSWER

\frac{ {w}^{2}  - 7w + 12}{ {w}^{2}  + w - 20 }

EXPLANATION


The given fraction is,

\frac{w - 3}{w + 5}

To get an equivalent fraction, we multiply both the numerator and the denominator by the same quantity that will give us

w²+w-20

in the denominator.


This implies that,

\frac{w - 3}{w + 5}  =  \frac{(w - 3)(w - 4)}{(w + 5)(w - 4)}

We multiply out the numerators and denominators using the distributive property to obtain,


\frac{w - 3}{w + 5}  =  \frac{ {w}^{2}  - 4w - 3w + 12}{ {w}^{2} - 4w + 5w - 20 }

This simplifies to

\frac{w - 3}{w + 5}  =  \frac{ {w}^{2}  - 7w + 12}{ {w}^{2}  + w - 20 }


5 0
3 years ago
Which value of y makes the inequality 3y^2 +2(y-5)>8 true?
Alex

Answer: D

Step-by-step explanation:

A) 3*0^2+2(0-5)>8

-10>8 -> not true

B) 3*(-1)^2+2(-1-5)>8

3*1+2*(-6)>8

3- 12>8

-9> 8 -> not true

C) 3*(-2)^2+2(-2-5)>8

3*4+2*(-7)>8

12-14>8

-2> 8 -> not true

D) ) 3*(-3)^2+2(-3-5)>8

3*9+2*(-8)>8

27-16>8

11> 8 -> true

4 0
3 years ago
How to write the slope intercept equation for points of (6,0) and (0,-5)?
Vadim26 [7]

Answer:

y=\frac{5}{6} x -5

Step-by-step explanation:

Hi there!

We are given the points (6,0) and (0, -5), and we want to write the equation of the line containing those points in slope-intercept form

Slope-intercept form can be written as y=mx+b, where m is the slope and b is the y intercept

First, we need to find the slope of the line

The formula for the slope can be written as \frac{y_2-y_1}{x_2-x_1}, where (x_1, y_1) and (x_2, y_2) are points

We have everything we need to find the slope, but let's label the points to avoid confusion

x_1=6\\y_1=0\\x_2=0\\y_2=-5

Now substitute these values into the formula

m=\frac{y_2-y_1}{x_2-x_1}

m=\frac{-5-0}{0-6}

Subtract

m=\frac{-5}{-6}

Simplify

m=\frac{5}{6}

The slope of the line is 5/6

Let's plug this value into the formula for the equation of the line in slope-intercept form.

We substitute 5/6 for m in y=mx+b:
y=\frac{5}{6}x+b

Now we need to find b

As stated before, b is the y intercept, which is the value where the line hits the y axis. The value of x at the y intercept is 0.

One of the points we were given is actually the y intercept; that point is (0, -5); notice how the value of x in this point is 0

The value of b is the value of y in this point, which is -5 in this case.

Substitute -5 as b in the formula.

y=\frac{5}{6} x -5

Hope this helps!

See more on this subject here (n.b. the answer uses a different way of solving): brainly.com/question/20891204

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Differentiate f(x)= square root of x times sin x
zysi [14]
Hello,

y= \sqrt{ x*sin(x) } \\

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