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n200080 [17]
3 years ago
7

Quadrilateral ABCD is transformed to create A′B′C′D′. Match the coordinates of A′ with the transformations that create it.

Mathematics
1 answer:
bulgar [2K]3 years ago
6 0

Answer:

The answer is below

Step-by-step explanation:

From the image attached, the coordinates of point A is at (2, -4).

Transformation is the movement of a point from its initial location to a new position. Types of transformation include dilation, reflection, translation and rotation.

If a point A(x, y) is reflected over the x axis, the new point is at  A'(x, -y)

If a point A(x, y) is translated a units right and b units down, the new location is at A'(x + a, y - b)

If a point A(x, y) is dilated by  factor of a, the new location is at A'(ax, ay)

If a point A(x, y) is  rotated 180° clockwise about the origin, the new location is at A'(-x, -y)

Hence:

For Quadrilateral ABCD is reflected over the x-axis, the coordinates of A' is at A'(2, 4)

For Quadrilateral ABCD is translated 2 units right and 1 unit down, the coordinates of A' is at A'(4, -5)

For Quadrilateral ABCD is dilated by a scale factor of 3, the coordinates of A' is at A'(6, -12)

For Quadrilateral ABCD is rotated 180° clockwise about the origin the coordinates of A' is at A'(-2, 4).

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Here we are given that the value of sinA is √3-1/2√2 , and we need to prove that the value of cos2A is √3/2 .

<u>Given</u><u> </u><u>:</u><u>-</u>

• \sf\implies sinA =\dfrac{\sqrt3-1}{2\sqrt2}

<u>To</u><u> </u><u>Prove</u><u> </u><u>:</u><u>-</u><u> </u>

•\sf\implies cos2A =\dfrac{\sqrt3}{2}

<u>Proof </u><u>:</u><u>-</u><u> </u>

We know that ,

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Simplify ,

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Subtract the numbers ,

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Simplify,

\sf\implies \boxed{\pink{\sf cos2A =\dfrac{\sqrt3}{2}} }

Hence Proved !

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