Answer:
U = 269.4 kJ
Explanation:
The energy required to place the three charges from infinity is given by:
In this case, you have that
q1 = q2 = q3 = q = 20uC
r12 = r13 = r23 = r = 2m
k: Coulomb constant = 8.98*10^9 NM^2/C^2
Then, you replace the values of q, r and k in the equation for the energy U:
hence, the required energy is 269.4 kJ
Answer:
Wavelength = 478.46 m
Explanation:
It is given that,
A local AM radio station broadcasts at a frequency of 627 kHz, f = 627000 Hz
We need to find the wavelength at which it is broadcasting. The wavelength is given by :
So, the wavelength is 478.46 m.
The correct answer to the question is-
CALCULATION:
As per the question, the electric field generated by the source charge is 1236 N/C at a distance of 4 m.
Hence , electric field E = 1236 N/C.
The distance of the point R = 4m
We are asked to calculate the charge possessed by the source.
The electric field produced by a source charge of Q at a distance R is calculated as -
Electric field E =
Here, is called the absolute permittivity of the free space.
Hence, the charge of source is calculated as -
Q =
=
=
=
=
Hence, the charge of source is