Answer:
First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.
For:
x
=
0
y
=
0
+
5
y
=
5
Or
(
0
,
5
)
For:
x
=
−
2
y
=
−
2
+
5
y
=
3
Or
(
−
2
,
3
)
We can now plot the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.
The boundary line will be solid because the inequality operator contains an "or equal to" clause.
graph{(x^2+(y-5)^2-0.125)((x+2)^2+(y-3)^2-0.125)(y-x-5)=0 [-20, 20, -10, 10]}
Now, we can shade the left side of the line.
graph{(y-x-5) >= 0 [-20, 20, -10, 10]}
Answer:
$8
Step-by-step explanation:
After the shoe purchase, her balance was $50 -45 = $5.
After depositing her babysitting earnings, her balance was $5+25 = $30.
After buying pizza, her balance was $30 -42 = -$12.
<em>Assuming no overdraft charge</em>, her balance after depositing her earnings was ...
-$12 +20 = $8
Sally's balance on Sunday was $8.

a) <u>n² + 6 </u>
~Here n is the number of term. So, put n = 1,2,3,4.... to get the term.
- If n = 1, first term = 1² + 6 = 7
- n = 2, second term = 10
- n = 3, third temm = 15
- n = 4, fourth term = 22
- n = 10, tenth term = 106
b) <u>3n²</u>
- If n = 1, first term = 3
- n = 2, second term = 12
- n = 3, third term = 27
- n = 4, fourth term = 48
- n = 10, tenth term = 300
Answer:
STEP 8
Step-by-step explanation:
Area of a triangle is equal to 1/2 b(h) so since you already have the height and base, all you need to do is input it back into the equation:

(10)(13)
Multiply 10 & 13 to equal

(130)
Then take half of 130 to get
A = 65