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slava [35]
3 years ago
9

A hiker carried 1 gallon of water on a hike. She drank 1/2 of the water when she stopped to rest and gave an equal amount of the

remaining water to each of 4 friends. What fraction of the 1 gallon of water did each friend receive?
Mathematics
1 answer:
m_a_m_a [10]3 years ago
6 0

Answer:

The answer to your question is 1/8

Step-by-step explanation:

Data

Total volume = 1 gallon

Water drank by the hiker = 1/2

Water drank by each of his friends = ?

Process

1.- Calculate the water that he gave to his friends

Water gave to his friends = 1 - 1/2

                                          = 1/2

2.- Calculate the amount of water each friend received.

            1/2 ÷ 4 = 1/8

3.- Conclusion

Each of the friends received 1/8 of the gallon.              

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Find the other endpoint of the line segment with the given endpoint and midpoint: endpoint(1.7, -4.6) midpoint (-7.5, 0.3).. (ne
Sergio [31]

Answer:

(- 16.7, 5.2 )

Step-by-step explanation:

let the coordinates of the endpoint be (x , y )

using the midpoint formula

consider the x- coordinate

\frac{1}{2}(x + 1.7) = - 7.5 ( multiply both sides by 2 )

x + 1. 7 = - 7.5 ( subtract 1.7 from both sides )

x = - 16.7

consider the y-coordinate

\frac{1}{2}(y - 4.6 ) = 0.3 ( multiply both sides by 2 )

y - 4.6 = 0.6 ( add 4.6 to both sides )

y = 5.2

endpoint = (- 16.7, 5.2 )


3 0
4 years ago
A computer and printer cost a total of $900. The cost of the computer is three times the cost of the printer. Find the cost of e
KiRa [710]

Answer:

C is computer

P is printer

3c + p = 900

750 + 150 = 900

So...

Computer = $750

Printer = $150

Brainiest plz :)

6 0
3 years ago
A) Find a recurrence relation for the number of bit strings of length n that contain a pair of consecutive 0s.
Fed [463]

Answer:

A) a_{n} = a_{n-1} + a_{n-2} + 2^{n-2}

B) a_{0} = a_{1} = 0

C)   for n = 2

  a_{2} = 1

for n = 3

 a_{3} = 3

for n = 4

a_{4} = 8

for n = 5

a_{5} = 19

Step-by-step explanation:

A) A recurrence relation for the number of bit strings of length n that contain a  pair of consecutive Os can be represented below

if a string (n ) ends with 00 for n-2 positions there are a pair of  consecutive Os therefore there will be : 2^{n-2} strings

therefore for n ≥ 2

The recurrence relation for the number of bit strings of length 'n' that contains consecutive Os

a_{n} = a_{n-1} + a_{n-2} + 2^{n-2}

b ) The initial conditions

The initial conditions are : a_{0} = a_{1} = 0

C) The number of bit strings of length seven containing two consecutive 0s

here we apply the re occurrence relation and the initial conditions

a_{n} = a_{n-1} + a_{n-2} + 2^{n-2}

for n = 2

  a_{2} = 1

for n = 3

 a_{3} = 3

for n = 4

a_{4} = 8

for n = 5

a_{5} = 19

7 0
3 years ago
Solve the equation n2 − 29 = 260 by using square roots.
umka2103 [35]

Answer:

Option A, n = ± 17

Step-by-step explanation:

<u>Step 1:  Add 29 to both sides</u>

n^2 - 29 = 260

n^2 - 29 + 29 = 260 + 29

n^2 = 289

<u>Step 2:  Square root both sides</u>

\sqrt{n^2} = \sqrt{289}

n = ± 17

Answer:  Option A, n = ± 17

4 0
3 years ago
14. Write a two-column proof.
scZoUnD [109]

Given:

\bold{ 8x=4y-20} \\\\ \bold{ y=13}

Prove:

\bold{x=4}

Solution:

\to \bold{8x=4y-20}..........(i)\\\\\to \bold{ y=13}........................(ii)

Putting the value of equation (ii) into the equation (i):

\to \bold{8x=4(13)-20}\\\\\to \bold{8x=52-20}\\\\\to \bold{8x=32}\\\\\to \bold{x=\frac{32}{8}}\\\\\to \bold{x= 4}\\\\

putting the value x into the equation (i):

\to \bold{8(4)=4y-20}\\\\\to \bold{32=4y-20}\\\\\to \bold{32+20=4y}\\\\\to \bold{52=4y}\\\\\to \bold{y=\frac{54}{4}}\\\\\to \bold{ y= 13.5}

Therefore, the value of x= 4

Learn more:

brainly.com/question/6219408

3 0
3 years ago
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