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3 years ago

I want yo nkow how to simplify

1 answer:

5 0

Remove parentheses by multiplying factors.
use exponent rules to remove parentheses in terms with exponents.
combine like terms by adding coefficients.
combine the constants.

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Scientific notation<br> how do I do this?

DENIUS [597]

Answer:

Post the questions and I'll do my best to help

Step-by-step explanation:

6 0

3 years ago

PLEASE HELP PLEASE PLEASE

liberstina [14]

<L = 1/2(130 - arc MK)

45 = 1/2(130 - arc MK)

90 = 130 - arc MK

arc MK = 130 - 90

arc MK = 40

Answer

arc MK = 40°

4 0

3 years ago

Please help me out :( these confuse me

Pavel [41]

Answer:

The answer to your question is : 33.3 (Rounded).

Step-by-step explanation:

I got this answer by dividing 19.6 by 20, which gave me 0.98.

Then, I multiplied 0.98 by 34, which gave me 33.32.

After rounding, 33.3 is your answer.

Hope this helped!!

8 0

3 years ago

Read 2 more answers

Write this equation in standard form:<br><br> y - 5 = 3(x - 2)

Iteru [2.4K]

I believe it is 3x-y=1

5 0

3 years ago

Read 2 more answers

Write an exponential function y = abx for a graph that includes (–3, 16) and (–1, 4) f(x) = 2(0.5)x f(x) = 0.5(2)x f(x) = 4(0.3)

Arisa [49]

Answer: $f(x)=2(0.5)^x$

Step-by-step explanation:

Given, the exponential function $y = ab^x$ for a graph that includes (–3, 16) and (–1, 4).

On putting these points, we will have

$f(-3)=16=ab^{-3}\\\\ f(-1)=4=ab^{-1}$

Now,

$\dfrac{f(-3)}{f(-1)}=\dfrac{16}{4}=\dfrac{ab^{-3}}{ab^{-1}}\\\\\Rightarrow\ \dfrac{4}{1}=\dfrac{b^{-3}}{b^{-1}}\\\\\Rightarrow\ \dfrac{4}{1}=\dfrac{b}{b^3}=\dfrac{1}{b^2}\\\\\Rightarrow\ b^2=\dfrac{1}{4}\\\\\Rightarrow\ b=\pm\dfrac{1}{2}=\pm0.5$

since the multiplicative factor cannot be negative, so b= 0.5.

At b= 0.5

$4=a(0.5)^{-1}\\\\\Rightarrow\ 4=a(\dfrac{1}{2})^{-1}\\\\\Rightarrow\ 4=a(2)\\\\\Rightarrow \ a=2$

So, the required function is $f(x)=2(0.5)^x$ .

3 0

4 years ago