<span> The product of two perfect squares is a perfect square.
Proof of Existence:
Suppose a = 2^2 , b = 3^2 [ We have to show that the product of a and b is a perfect square.] then
c^2 = (a^2) (b^2)
= (2^2) (3^2)
= (4)9
= 36
and 36 is a perfect square of 6. This is to be shown and this completes the proof</span>
Answer:
<h2>LCD = 9</h2>
Equivalent Fractions with the LCD
1/3 = 3/9
5/9 = 5/9
Solution:
Rewriting input as fractions if necessary:
1/3, 5/9
For the denominators (3, 9) the least common multiple (LCM) is 9.
LCM(3, 9)
Therefore, the least common denominator (LCD) is 9.
Calculations to rewrite the original inputs as equivalent fractions with the LCD:
1/3 = 1/3 × 3/3 = 3/9
5/9 = 5/9 × 1/1 = 5/9
9514 1404 393
Answer:
11
Step-by-step explanation:
4 × (2 3/4) = 4×2 + 4×(3/4) = 8 + 3 = 11
or
4 × (2 3/4) = 4 × 11/4 = 11
Answer:
14$
Step-by-step explanation:
Please mark brainliest
Answer:
7×10³+3×10²+4×10¹+2×10 or 7.342×10³
