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devlian [24]
3 years ago
15

1) A speed walker covered 4 1/2 mi in 3/4 hour. How far will he walk with the same pace in 2 hours? 3 hours? 3.5 hours?

Mathematics
1 answer:
Savatey [412]3 years ago
3 0

You can solve this with proportion

1)    For 2h

9/2 mile : 3/4h = x mile : 2h => (3/4)x=(9/2)*2 => (3/4)x=9 => x=9*(4/3)= 12miles

For 3h => (3/4)x=(9/2)*3 When we divide equation with 3 we get

x/4=9/2 => x=(9/2)*4=18 miles

2)  2 combine : 320 acres = 7 combines : x acres +: 2x= 320*7 =>

x= (320*7)/2 = 160 * 7 = 1120 acres

Good luck!!!


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Answer:

The base of the triangle is 6cm.

Step-by-step explanation:

The find the base of a triangle, use this formula.

Formula : 1/2 x b x h

<em>If you would like some more explanation, see the attached image.</em>

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Write 0.70 to 0.14 as a fraction in simplest form
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\cfrac{0.70}{0.14}=  \cfrac{70}{14}= \cfrac{35}{7}= \cfrac{5}{1}
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Working independently, Tina can do a certain job in 12 hours. Working independently, Ann can do the same job in 9 hours. If Tina
Leona [35]

Answer:

Ann would need 3 h to complete the remainder of the Job.

Step-by-step explanation:

Step 1.

The "speed" that each girl has to do the work is determined as:

  • Tina: \frac{1}{12h}, it means that Tina complete one twelveth of the job each hour.
  • Ann: \frac{1}{8h}, it means the Ann completes one eighth of the job each hour.

Step 2.

The amount of work done by Tina in 9 hours, is obtain multiplying by the "speed" calculated in step 1:

Amount of work done= 8 h*\frac{1}{12h} = \frac{2}{3}. It means that <em>Tina completes two thirds of the work in 9 h.</em>

Step 3.

The remaining job is calculated as 1-\frac{2}{3}=\frac{1}{3}. It means that <em>still remains is one third of the job to be completed</em>.

Step 4.

The time required for Ann to complete the job is calculated dividing the remaining of the job by the "speed" of Ann to do the job.

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3 0
3 years ago
4(3h+7)/4+h for h=-2
fomenos
The answer would be 2
8 0
3 years ago
Find the 57th derivative of y = cos(7x).
mel-nik [20]
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First derivative = -7sin(7x)

Second derivative = - (7^2)cos(7x)

3rd derivative = (7^3)sin(7x)

4th derivative =  (7^4) cos(7x)

5th derivative = -(7^5) sin (7x)

6th derivative = -(7^6) cos(7x)

nth derivative ?

Analysis and conclusion

If n is multiple of 4 or a number before a multiple of 8 the sign is positive

If n is one or two numbers after a multiple of 4 the sign is negative.

7 is raised to exponent n

if n is odd the function is sin(7x), if n is even the function is cos(7x)

n = 57 => odd, and it is a number after 56 which is a multiple of 4 => negative sign

Therefore, the 57th derivative = - (7^57)sin(7x)

6 0
2 years ago
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