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puteri [66]
3 years ago
10

When solving a system of equations, Jared found y = x + 10 for one equation and substituted x + 10 for y in the other equation.

Nicole found x = y – 10 for the same equation and substituted y – 10 for x in the other equation. Who is correct? Explain.
Mathematics
2 answers:
DedPeter [7]3 years ago
8 0

Answer:

Both Jared and Nicole are correct. You can solve for either variable and use the equivalent expression to create a one-variable equation. Then you can solve. Jared would have created a one-variable equation that can be used to solve for x, whereas Nicole would have created a one-variable equation that can be used to solve for y

Step-by-step explanation:

This is the sample answer that Ingenuity has offered.

myrzilka [38]3 years ago
5 0
Both are correct they just chose a different variable to solve for first. they will both get correct answers if they do the rest correctly.
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Compare the fraction 3/5 to 1/2 and then compare 2/6 to 1/2. Use symbols in your answer
worty [1.4K]
Hello there!

"Compare the fraction 3/5 to 1/2 and then compare 2/6 to 1/2. Use symbols in your answer"


To make this easier, we will make it so that both fractions in each pair has like bases.

To make 3/5 and 1/2 have a like base, we must make the denominators 10. To do this, we will do the following:

(3*2)/(5*2) = 6/10

(1*5)/(2*5) = 5/10

Now we can easily compare and not worry about the denominator

So, let's just look at the numerators. 

Which is greater, 5 or 6? We know 6 is greater, so:

6/10 > 5/10

That means:

3/5 > 1/2

Now, we must do the same for 2/6 and 1/2

We will make them both 6. So, we can leave 2/6 alone

2/6

(1*3)/(2*3) = 3/6

Now we have 2/6 and 3/6

Which is greater, 3 or 2. The answer to that is 2. So:

3/6 > 2/6

This means that 1/2 > 2/6


Our answers are:

1. 3/6 > 2/6

2. 1/2 > 2/6


I hope I was able to help you!

~ Fire




7 0
3 years ago
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I am Lyosha [343]

Answer:

y' = xe^{x}(2 + x)

Step-by-step explanation:

If we have a product function y, in the following format

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In this problem, we have that:

y = x^{2}e^{x}

So

f(x) = x^{2}, f'(x) = 2x, g(x) = e^{x}, g'(x) = e^{x}

The derivative of the function is:

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y' = 2xe^{x} + x^{2}e^{x}

y' = e^{x}(2x + x^{2})

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Answer:

<h3>The answer is 206 I believe</h3>

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