For f(x)=1/x^2-3
Find
A) f(3)
B) f(2-h)
If f(x)=1/x^2-3, then f(3) = 1 / 3^2 - 3. The exponentiation here must be carried out first: f(3) = 1/9 - 3. Then f(3) = 1/9 - 27/9 = -26/9
If f(x)=1/x^2-3, then f(2-h) = 1 / [2-h]^2 - 3. This result may be left as is or expanded. In expanded form, we have:
1
f(2-h) = ------------------ - 3
4-4h +h^2
Step-by-step explanation:
29x - 3 + 15x + 7 = 180° because these two angles are supplementary
if we add like terms
44x + 4 = 180
44x = 176 divide both sides by 44
x = 4
29x - 3 = 13y - 17 because alternate exterior angles has same measurement
since we found the value of x let's rewrite the equation
4 × 29 - 3 = 13y - 17
113 = 13y - 17
130 = 13y divide both sides by 13
10 = y
Answer:
Y=3
Step-by-step explanation:
-1= 1/2
1/2=-1
x=-1
y=3
Hope this helps!
To graph the absolute value graph the function y=f(x). Anything above the x- axis, stays above it.
That is what it looks like
