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Vsevolod [243]
3 years ago
8

Determine whether each ordered pair is a solution of the inequality-3x-4y<6

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
5 0

Answer:

it's (6,0) I can't explain though

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adiocarbon dating of blackened grains from the site of ancient Jericho provides a date of 1315 BC ± 13 years for the fall of the
Zigmanuir [339]

Answer:

\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659 and \left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661

Step-by-step explanation:

The equation of the isotope decay is:

\frac{m(t)}{m_{o}} = e^{-\frac{t}{\tau} }

14-Carbon has a half-life of 5568 years, the time constant of the isotope is:

\tau = \frac{5568\,years}{\ln 2}

\tau \approx 8032.926\,years

The decay time is:

t = 1315\,years + 2007\,years \pm 13\,years (There is no a year 0 in chronology).

t = 3335 \pm 13\,years

Lastly, the relative amount is estimated by direct substitution:

\frac{m(t)}{m_{o}} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\mp\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{min} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{-\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659

\left(\frac{m(t)}{m_{o}} \right)_{max} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661

4 0
3 years ago
A line includes the point (7,5)has a slope of 1.What is its equation in slope intercept form?
Lina20 [59]

Given:

Point( 7, 5)

x = 7 and y=5

slope(m) = 1

We need to first find the intercept.

Substitute x=7, y=5 and m=1 into y=mx + b and solve for intercept(b)

5 = 1(7) + b

5 = 7 + b

5 - 7 = b

-2 = b

Now, form the equation by substituting the value of the slope and intercept into y=mx + b

y = x - 2

7 0
1 year ago
What is length of chord UV?
prohojiy [21]
Your answer is C. 16 this is the possible answer
5 0
3 years ago
Which is the best estimate for the area of the figure above?
nekit [7.7K]

Answer:

So I'd say 20in^2 or 22in^2.

Step-by-step explanation:

I decided to make it into a full pentagon shape to just estimate.

So a pentagons sides are all equal so I counted the amount in boxes on the sides of the regular shape and most of them would be 3.5 if you changed the shape into a pentagon.

And I got:

--> 21.076

5 0
3 years ago
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Liz runs the fastest
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3 years ago
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