So this is a Pythagorean problem where
A^2+b^2=c^2
a is 2
X is b
5 is c
Plug that into the equation and get
4+b^2=25
B^2=21
B=sqrt(21)=4.6kilometer
Answer:
y= -4
Step-by-step explanation:
Answer: Work done by the particle is 78 N.
Step-by-step explanation:
If C is the path the particle follows, then work done is 
.
According to the question the force 
and all four points are in the plane 
.
therefore, if S is the at surface with boundary C, so that S is the portion of the plane over the rectangle D=[0,2]\times [0,4].
Now,
By the Stoke's theorem:
![\int_{C}^{}F.dx=\iint_{s}^{}curlF.dS\\\\=\iint_{D}^{}[-8y(0)-2z\left ( \frac{1}{4} \right )+5y]dA\\\\=\iint_{D}^{}\left ( -\frac{1}{2}z+5y \right )dA](https://tex.z-dn.net/?f=%5Cint_%7BC%7D%5E%7B%7DF.dx%3D%5Ciint_%7Bs%7D%5E%7B%7DcurlF.dS%5C%5C%5C%5C%3D%5Ciint_%7BD%7D%5E%7B%7D%5B-8y%280%29-2z%5Cleft%20%28%20%5Cfrac%7B1%7D%7B4%7D%20%5Cright%20%29%2B5y%5DdA%5C%5C%5C%5C%3D%5Ciint_%7BD%7D%5E%7B%7D%5Cleft%20%28%20-%5Cfrac%7B1%7D%7B2%7Dz%2B5y%20%5Cright%20%29dA)
![\int_{0}^{2}\left [ \frac{39}{16}y^2 \right ]_{0}^{4}dx\\\\=\int_{0}^{2}39\, \, dx\\\\=39\times 2\\\\=78 \, N](https://tex.z-dn.net/?f=%5Cint_%7B0%7D%5E%7B2%7D%5Cleft%20%5B%20%5Cfrac%7B39%7D%7B16%7Dy%5E2%20%5Cright%20%5D_%7B0%7D%5E%7B4%7Ddx%5C%5C%5C%5C%3D%5Cint_%7B0%7D%5E%7B2%7D39%5C%2C%20%5C%2C%20%20dx%5C%5C%5C%5C%3D39%5Ctimes%202%5C%5C%5C%5C%3D78%20%5C%2C%20N)
Answer: y-3=4(x+1) in point-slope form and y=4x+7 in slope intercept form
Step-by-step explanation:
You can find the point-slope form by plugging the numbers into the following: y-y₁=m(x-x₁).
You will end up with y-(3)=(4)(x-(-1)) which when simplified equals y-3=4(x+1).
To find slope intercept form you know need to isolate y and simplify.
Adding 3 to both sides results in y=4(x+1)+3.
If you then distribute you get y=4x+4+3 which simplifies to y=4x+7.
Answer:
B) 4
Step-by-step explanation:
Tan is opposite/adjacent. That means that 3 is the opposite side while 4 is the adjacent side.
