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Ilya [14]
3 years ago
9

Marine scientists categorize signature whistles of bottlenose dolphins by typelong dash—type ​a, type​ b, type​ c, etc. In one s

tudy of a sample of 185 whistles emitted from bottlenose dolphins in​ captivity, 100100 were categorized as type a whistles. a. Estimate the true proportion of bottlenose dolphin signature whistles that are type a whistles. Use a 9595​% confidence interval.
Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
3 0

Answer:

The 95​% confidence interval for the true proportion of bottlenose dolphin signature whistles that are type a whistles is (0.4687, 0.6123).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 185, \pi = \frac{100}{185} = 0.5405

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5405 - 1.96\sqrt{\frac{0.5405*0.4595}{185}} = 0.4687

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5405 + 1.96\sqrt{\frac{0.5405*0.4595}{185}} = 0.6123

The 95​% confidence interval for the true proportion of bottlenose dolphin signature whistles that are type a whistles is (0.4687, 0.6123).

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Find the 7th term of the expansion of (3c + 2d)9.
SIZIF [17.4K]
\bf (3c+2d)^9\\\\
-------------------------------\\\\

\begin{array}{crcll}
term&&value\\
-----&&-----\\
1&&(3c)^9(2d)^0\\
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\end{array}

now.. if you notice, the exponent for the 1st term, is dropping on each term subsequently, start with highest, 9 in this case, and drops drops drops, till on the last term, will be 0

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for example, how did we get 84 for the 4th term?   (36 * 7) / 3 = 84

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