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kupik [55]
3 years ago
11

Help me please numbers 7 and 8

Mathematics
1 answer:
Olegator [25]3 years ago
3 0
7. plot the points and then measure the height and base 
then find the area of parallelogram 1/2*b*h
8. draw a horizontal line on any point y axis
and then plot r go to 0 and then up one over one repeat the steps and then down one to the right one
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5:3 equivalent fraction
lana66690 [7]

Answer:

5/3

Step-by-step explanation:

A ratio is just a fraction comparing two quantities.

Ex: For every 5 trees, there were 3 elephants

This, into a fraction, would take the first number and make it the numerator and the second number into a the denominator.

Just think of the colon as a slash or a divide sign

Vote Brainliest, Thx :)

3 0
3 years ago
5 × 10/12 what is the product?
joja [24]

Answer:

Step-by-step explanation:

10 divided by 12= 0.83

0.83 times 5= 4.16 or  26/625

3 0
4 years ago
X/2-7=9 solve the equation. help asap
Neporo4naja [7]

Answer:

x=32

Step-by-step explanation:

x/2-7=9

1/2x-7=9

add seven to both sides

1/2x=16

multiple both sides by two

x=32

3 0
4 years ago
7
Vinvika [58]

Answer:

126 square units

Step-by-step explanation:

Area of section 1 is 8 square units which is triangle and,

Area of triangle is =  \frac{1}{2}\times b\times h

b= 2 units and height =8 units

So,

Area of section 1  =  \frac{1}{2}\times 2\times 8=8 \quad\text{ square units}

Same Area is of section 2 which is also a triangle and has same base and height.

So,

Area of Section 2 = \frac{1}{2}\times 2\times 8=8 \quad\text{ square units}

Now the Area of section 3 which is square with side of 10 units

So,

Area of section 3 =  a^{2} =10\times10=100\quad \text{square units}

Total Area of Trapezoid = 8+8+100=126 \quad \text{square units}

5 0
2 years ago
What are the solutions of the equation<br> x^2 - 30 = x?
sashaice [31]

Answer:

x = 6 , − 5

Step-by-step explanation:

Move  x   to the left side of the equation by subtracting it from both sides.  x^ 2 − 30 − x = 0

x2-30-x=0

Use the quadratic formula to find the solutions. − b ± √ b 2 − 4 ( a c )/ 2 a  

-b±b2-4(ac)/2a  

Substitute the values  

a = 1  ,  b = − 1  , and  c = − 30  

into the quadratic formula and solve for  x

x . 1 ± √ ( − 1 ) 2 − 4 ⋅ ( 1 ⋅ − 30 )/ 2 ⋅ 1    

Simplify.

x = 1 ± 11/ 2    

The final answer is the combination of both solutions.

x = 6 , − 5

8 0
4 years ago
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