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kupik [55]
2 years ago
11

Help me please numbers 7 and 8

Mathematics
1 answer:
Olegator [25]2 years ago
3 0
7. plot the points and then measure the height and base 
then find the area of parallelogram 1/2*b*h
8. draw a horizontal line on any point y axis
and then plot r go to 0 and then up one over one repeat the steps and then down one to the right one
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Cam and Madison were investing money into two different accounts. They both invested $550
Arlecino [84]

Answer:

After 5 years, Cam's account will have $ 616.04 while Madison's account will have $ 638.53.

Step-by-step explanation:

Given that Cam and Madison were investing money into two different accounts, both investing $ 550 each, and Cam invested into an account at an annual interest rate of 2.7% compounded monthly while

Madison invested into an account that had an annual interest rate of 3% compounded quarterly, to determine the balances of both accounts after 5 years, the following calculations must be performed:

Cam

X = 550 (1 + 0.027 / 12) ^ 5x12

X = 550 (1 + 0.027 / 12) ^ 60

X = 616.04

Madison

X = 550 (1 + 0.03 / 3) ^ 5x3

X = 550 (1 + 0.03 / 3) ^ 15

X = 638.53

Thus, after 5 years, Cam's account will have $ 616.04 while Madison's account will have $ 638.53.

4 0
3 years ago
When Roberto got a puppy from the shelter it weight 11 pounds. the puppy gained 40% of its original weight in the first month th
Valentin [98]
Since 40%=40/100=4/10, we can divide 11 by 10 and multiply that by 4 to get the weight gained, which is 1.1*4=4.4. The weight gained paired with the starting weight = 10+4.4=14.4
6 0
3 years ago
The following proportion could be used to change from gallons to which measure.
antoniya [11.8K]

Answer:

C. quarts

Step-by-step explanation:

5 0
2 years ago
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If two polynomial equations have real solutions, then will the equation that is the result of adding, subtracting, or multiplyin
kirill115 [55]

No. A polynomial equation in one variablel ooks like P(x) = Q(x), where P and Q are polynomials.

Consider polynomial equations x^2 = 3 and x^2 = 1.

Obviously they have real solutions.

Subtract the two polynomial equations:

(x^2 - x^2) = (3 - 1)

0 = 2...

We get the polynomial equation 0 = 2. We call this a polynomial equation because single constants are also by definition polynomials.

Obviously 0 = 2 has no real solution.

3 0
2 years ago
4. Kevin is using his scanner to make a smaller version of the school logo to put in the yearbook.
vredina [299]

Answer:

scale factor 2.5

Step-by-step explanation:

3 0
3 years ago
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