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dezoksy [38]
3 years ago
15

Find the product. (n + 7)(n - 2) n² - 5n - 14 n² + 5n - 14 n² - 5n + 14

Mathematics
2 answers:
svp [43]3 years ago
6 0
(n+7)(n-2)
=n•n+(-2)•n+7•n+7•(-2)
=n²-2n+7n-14
=n²+5n-14. In conclusion, the product of (n+7) and (n-2) or (n+7)(n-2)=n²+5n-14. Hope it help!
Maslowich3 years ago
3 0
The answer is n^2 + 5n - 14.


(n+7)(n-2)\\\\n*n+(-2)*n+7*n+7*(-2)\\\\n^{2}-2n+7n-14\\\\n^{2}+5n-14
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Answer:

The factorized expression is (-5) × (t - 2.747) ×(t - 1.747)

Step-by-step explanation:

The given expression is -5·t² + 5·t + 24

To factorize the expression by completing the square method, we equate the expression to zero to get;

-5·t² + 5·t + 24 = 0

WE divide by -5 to get;

t² - t - 24/5 = 0

t² - t = 24/5

t² - t + 1/4 = 24/5 + 1/4

(t - 1/2)² = 5.05

t - 1/2 = ±√5.05

t = 1/2 + √5.05, 1/2 - √5.05

The factorized expression becomes;

(t - 1/2 + √5.05) and (t - 1/2 - √5.05)

Which gives;

(t - 2.747) ×(t - 1.747)

The factorized expression is (-5) × (t - 2.747) ×(t - 1.747).

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Given loga (m) = 10 and loga (n) = 25 , find loga (m * n ^ 2)
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The result of the log function log_a (m * n ^ 2)  is 60

According to the law of logarithm if log_ab=y then b=a^y

Given the following expressions

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This can be expressed as

m =a^{10} \ and \ n = a^{25}

Substitute the value of m and n into the expression log_a (m * n ^ 2) to have:

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This shows that the result of the log function log_a (m * n ^ 2)  is 60

Learn more here: brainly.com/question/12049968

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