3 years ago

Find the product. (n + 7)(n - 2) n² - 5n - 14 n² + 5n - 14 n² - 5n + 14

2 answers:

6 0

(n+7)(n-2)
=n•n+(-2)•n+7•n+7•(-2)
=n²-2n+7n-14
=n²+5n-14. In conclusion, the product of (n+7) and (n-2) or (n+7)(n-2)=n²+5n-14. Hope it help!

Maslowich3 years ago

3 0

The answer is n^2 + 5n - 14.

$(n+7)(n-2)\\\\n*n+(-2)*n+7*n+7*(-2)\\\\n^{2}-2n+7n-14\\\\n^{2}+5n-14$

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