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Aleks [24]
3 years ago
11

Use function notation to represent the area of a circle whose circumference is 136cm

Mathematics
1 answer:
Nimfa-mama [501]3 years ago
7 0

Answer:

A(\frac{68}{\pi})=\frac{4624}{\pi}

Step-by-step explanation:

The given circle has circumference 136cm.

The formula for circumference is C=2\pi r

This implies that:

136=2\pi r

\frac{136}{2\pi}=r

\frac{68}{\pi}=r

The area of a circle is given as A(r)=\pi r^2

When r=\frac{68}{\pi}

A(\frac{68}{\pi})=\pi*(\frac{68}{\pi})^2

A(\frac{68}{\pi})=\pi*\frac{(68)^2}{\pi^2}

A(\frac{68}{\pi})=\frac{4624}{\pi}

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19) Two of the dozen eggs in a carton are cracked. About what percent of the carton is not cracked? (Round to the nearest whole
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Answer:

83%%

Step-by-step explanation:

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What are the exact solutions of x2 − 5x − 7 = 0, where x equals negative b plus or minus the square root of b squared minus 4 ti
Marat540 [252]

Answer:

x = \frac{5 + \sqrt{53}}{2}  or  x = \frac{5 - \sqrt{53}}{2}

Step-by-step explanation:

Given

x^2 - 5x - 7 = 0

Required

Solve for x using:

x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

First, we need to identify a, b and c

The general form of a quadratic equation is:

ax^2 + bx + c = 0

So, by comparison with x^2 - 5x - 7 = 0

a = 1     b = -5      c = -7

Substitute these values of a, b and c in

x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

x = \frac{-(-5) \± \sqrt{(-5)^2 - 4 * 1 * -7}}{2 * 1}

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Split the expression to two

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To solve further in decimal form, we have

x = \frac{5 + 7.28}{2}  or  x = \frac{5 - 7.28}{2}

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