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Pani-rosa [81]
4 years ago
10

How do you solve: 21 11/12 plus 17 5/12

Mathematics
2 answers:
GarryVolchara [31]4 years ago
6 0
The problem is 21  \frac{11}{12} + 17 \frac{5}{12}

Add the whole numbers

21 + 17 = 38

Match up the fractions and make sure the denominators are the same (they are)

\frac{11}{12}  +  \frac{5}{12} =  \frac{16}{12}

Break down the fraction 

16 ÷ 12 = 1 \frac{4}{12}

Reduce-You need to find a common factor for both the numerator and denominator

4 ÷ 4 = 1

12 ÷ 4 = 3

Combine everything

38 +  1\frac{1}{3} =39  \frac{1}{3}

Answer: 39  \frac{1}{3}







ArbitrLikvidat [17]4 years ago
6 0
If you would like to calculate 21 11/12 + 17 5/12, you can do this using the following steps:

21 11/12 + 17 5/12 = 263/12 + 209/12 = (263 + 209) / 12 = 472/12 = 118/3 = 39 1/3

The correct result would be 39 1/3.
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Alternate Hypothesis, H_A : \mu < 185 minutes     {means that the mean duration of 15-sided union rugby games has decreased after the meeting}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                            T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean duration of 15-sided union rugby games = 179 min

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So, <u><em>the test statistics</em></u>  =  \frac{179-185}{\frac{12}{\sqrt{36} } }  ~ t_3_5

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The value of t test statistics is -3.

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Since our test statistic is less than the critical value of t as -3 < -2.437, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

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