Answer:
physical property and chemical properties are similarly because they both have to do with atoms and convey on the same platform
Use your units . . . "period" is time, so you know that you have to
set up your fraction with time in the numerator.
10 seconds / 4 waves =
(10/4) sec/wave = 2.5 seconds per wave.
______________________________________
Notice how the first answer set it up exactly backwards.
He would have seen his mistake immediately if he had
kept the units.
He started out by saying . . . . P = N / t
Keeping the units, P = (waves) / (second)
The answer will have units of "waves per second" .
That's frequency, not period.
Answer:
A(many people think that no energy or matter exists outside the universe)
Explanation:
According to the information presented, it is necessary to take into account the concepts related to mass flow, specific potential energy and the power that will determine the total work done in the system.
By definition we know that the change in mass flow is given by
![\dot{m} = \rho AV](https://tex.z-dn.net/?f=%5Cdot%7Bm%7D%20%3D%20%5Crho%20AV)
![\dot {m} = \rho Q](https://tex.z-dn.net/?f=%5Cdot%20%7Bm%7D%20%3D%20%5Crho%20Q)
Remember that the Discharge is defined as Q = AV, where A is the Area and V is the speed.
Substituting with the values we have we know that the mass flow is defined by
![\dot{m} = 1000*0.03](https://tex.z-dn.net/?f=%5Cdot%7Bm%7D%20%3D%201000%2A0.03)
![\dot{m} = 30kg/s](https://tex.z-dn.net/?f=%5Cdot%7Bm%7D%20%3D%2030kg%2Fs)
To calculate the power we need to obtain the specific potential energy, which is given by
![\Delta pe = gh](https://tex.z-dn.net/?f=%5CDelta%20pe%20%3D%20gh)
![\Delta pe = 441m^2/s^2](https://tex.z-dn.net/?f=%5CDelta%20pe%20%3D%20441m%5E2%2Fs%5E2)
So the power needed to deliver the water into the storage tank would be
![\dot {E} = \dot{m}\Delta pe](https://tex.z-dn.net/?f=%5Cdot%20%7BE%7D%20%3D%20%5Cdot%7Bm%7D%5CDelta%20pe)
![\dot {E} = 30*441](https://tex.z-dn.net/?f=%5Cdot%20%7BE%7D%20%3D%2030%2A441)
![\dot{E} = 13230W = 13.23kW](https://tex.z-dn.net/?f=%5Cdot%7BE%7D%20%3D%2013230W%20%3D%2013.23kW)
Finally the mechanical power that is converted to thermal energy due to friction effects is:
![\dot{W}_f = \dot{W}_s - \dot{E}](https://tex.z-dn.net/?f=%5Cdot%7BW%7D_f%20%3D%20%5Cdot%7BW%7D_s%20-%20%5Cdot%7BE%7D)
![\dot{W}_f 20-13.23](https://tex.z-dn.net/?f=%5Cdot%7BW%7D_f%2020-13.23)
![\dot{W} = 6.77kW](https://tex.z-dn.net/?f=%5Cdot%7BW%7D%20%3D%206.77kW)
Therefore the mechanical power due to friction effect is 6.77kW