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3 years ago

What force is used to make maglev trains run along their tracks?

1 answer:

8 0

Hi, thank you for posting your question here at Brainly.

Maglev trains are called as such, since they are derived from "magnetic levitation". The force that makes them run along their tracks is through attraction and repulsion forces brought about by the magnets.

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A force of 124 newtons pushed a 12kg object forward 13 meters. How much work is being done?

MariettaO [177]

Answer:

Work = Force * Distance

Here,

force = 124 N

distance = 13m

Thus, Work = 124 * 13 = 1612 joules(J)

5 0

2 years ago

A man steps off a diving platform lands in the water below. If he were to miss the water and land on the concrete, his change in

kari74 [83]

Answer:

if he were to land on concrete, he would most likely die and stop all momentum and for the water, he'd most likely live/die (mostly live) and slow momentum to a stop and rise up to the surface

Explanation:

that's the explanation now i gotta execute order 66

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3 years ago

I just... I don't know man I suck at physics :(

lys-0071 [83]

Answer:

Explanation:

The velocity is 340, but the distance is not. Here's how you do this:

You need to find out the velocity of the that sound in that temp which has a formula of

v = 331.5 + .606T where T is the temp in Celcius. Filling in and using the correct number of sig dig:

v = 331.5 + .606(20) and

v = 331.5 + 10 and

v = 340 m/s. Now we need to use that in d = vt:

d = 340(2.00) so

d = 680 m

3 0

3 years ago

Read 2 more answers

You toss a ball straight up with an initial speed of 30m/s. How high does it go, and how long is it in the air (neglecting air r

Brut [27]

Explanation:

Given that,

A ball is tossed straight up with an initial speed of 30 m/s

We need to find the height it will go and the time it takes in the air.

At its maximum height, its final speed, v = 0 and it will move under the action of gravity. Using equation of motion :

v = u +at

Here, a = -g

v = u -gt

i.e. u = gt

$t=\dfrac{u}{g}\\\\t=\dfrac{30\ m/s}{9.8\ m/s^2}\\\\t=3.06\ s$

So, the time for upward motion is 3.06 seconds. It means that it will in air for 3.06×2 = 6.12 seconds

Let d is the maximum distance covered by it.

$d=ut-\dfrac{1}{2}gt^2$

Putting all values

$d=30(3.06)-\dfrac{1}{2}\times 9.8\times (3.06)^2\\\\d=45.91\ m$

Hence, it will go to a height of 45.91 m and it will in the air for 6.12 seconds.

8 0

3 years ago

Choose which best describes the following argument:

DaniilM [7]

Answer: The answer is a

Explanation:

5 0

3 years ago

Read 2 more answers