Answer:
<em>The resultant velocity has a magnitude of 38.95 m/s</em>
Explanation:
<u>Vector Addition</u>
Given two vectors defined as:
The sum of the vectors is:
The magnitude of a vector can be calculated by
Where x and y are the rectangular components of the vector.
We have a plane flying due west at 34 m/s. Its velocity vector is:
The wind blows at 19 m/s south, thus:
The sum of both velocities gives the resultant velocity:
The magnitude of this velocity is:
d = 38.95 m/s
The resultant velocity has a magnitude of 38.95 m/s
Answer:
Explanation:
The electrostatic attraction between the nucleus and the electron is given by:
(1)
where
k is the Coulomb's constant
Ze is the charge of the nucleus
e is the charge of the electron
r is the distance between the electron and the nucleus
This electrostatic attraction provides the centripetal force that keeps the electron in circular motion, which is given by:
(2)
where
m is the mass of the electron
v is the speed of the electron
Combining the two equations (1) and (2), we find
And solving for v, we find an expression for the speed of the electron:
Answer:
4 kg at 30 m/s
Explanation:
comparing in pair, the 3rd is more than the 1st, and the 4th is more than the 2nd, so it boils down to the lasts two. calculate, and im pretty sure you get 4 kg at 30 m/s...
Answer:
0.8 m
Explanation:
Draw a free body diagram. There are three forces:
Weight force mg pulling down,
Normal force N pushing up,
and friction force Nμ pushing towards the center.
Sum of forces in the y direction:
∑F = ma
N − mg = 0
N = mg
Sum of forces in the centripetal direction:
∑F = ma
Nμ = m v²/r
Substitute and simplify:
mgμ = m v²/r
gμ = v²/r
Write v in terms of ω and solve for r:
gμ = ω²r
r = gμ/ω²
Plug in values:
r = (10 m/s²) (0.5) / (2.5 rad/s)²
r = 0.8 m
