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Alex777 [14]
2 years ago
12

Write an equation of a function with each domain:

Mathematics
1 answer:
Aliun [14]2 years ago
8 0

Answer:  a. y = \sqrt{x} -2        

Step-by-step explanation:

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The table represents a function what is f(-2)
wolverine [178]
\bf \begin{array}{ccll}
x&f(x)\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
-6&3\\
-2&\boxed{1}\\
0&4\\
3&-2
\end{array}\qquad \qquad f(\stackrel{x}{-2})\implies x=-2
8 0
3 years ago
Read 2 more answers
Keisha went into a park at 1:30 pm she hiked for 1 hour 35 minutes. Then she went to the picnic area for 45 minutes and left the
nata0808 [166]

Answer:

3:50pm

Time Keisha went to the park- 1:30pm

Time spent for hiking- 1hour 35 minutes

Time spent at the picnic area- 45 minutes

1: 30pm

<u>+1. 35mi</u>n

<u> 2: 65pm</u>

But 60 minutes is 1 hour so the 65 will be changed to 1 hour 5 minutes making it

3: 05pm

3: 05pm

<u>+0: 45min</u>

<u> 3: 50pm</u>

Hence the time Keisha left the park was 3:50pm

3 0
2 years ago
Hi pls help.you do not have to do all 3. just either one will be ok pls explain as well:) thank you
noname [10]

Answer:

{7a^{5}b^{5} c\\

Step-by-step explanation:

 \frac{28a^{8}b^{6} c^{3}  }{4a^{3}bc^{2}  }

→ First look at the first term of each expression and see if they can be simplified, and they can

\frac{7a^{8}b^{6} c^{3}  }{a^{3}bc^{2}  }

→ Now look at the a terms, since a larger one is at the top, you subtract

\frac{7a^{5}b^{6} c^{3}  }{bc^{2}  }

→ Now simplify the b and c terms

{7a^{5}b^{5} c

3 0
2 years ago
a car needw fixing and abe can fix it for $70 per hour with a $130 part, but gabe can fix it for $80 an hour with a $40 part. ho
Zolol [24]
70 + 130 = 200
This would be Abe’s one hour of work and the part
80 + 80 + 40 = 200
This would be Gabe’s two hours of work and the part
6 0
3 years ago
Read 2 more answers
Based only on the information given in the diagram, which congruence
romanna [79]
<h3>1 Answer: Choice D) SAS</h3>

=================================================

Explanation:

LA stands for Leg Angle. More specifically, the angle is an acute angle. This theorem only works for right triangles. We see that ED = LK which is one pair of congruent leg segments. So that takes care of the L part of LA. However, we don't know anything about the acute angles. We don't know if angle E = angle L, or if angle F = angle M, or something along those lines. We need angle markers to tell us or not.

In short, we only have half the info needed for LA, so we must cross choice A off the list.

----------------

HA stands for hypotenuse angle, or hypotenuse acute angle, and this rule only applies for right triangles. We don't know anything about the hypotenuse lengths if they are the same or not.

Similar to choice A, we don't know anything about the acute angles either.

Those two facts mean we must cross off choice B.

----------------

AAS stands for Angle Angle Side. The order is important because the side is not between the angles. The diagram only shows one pair of angles that are congruent to one another. That pair being the 90 degree angles indicated with the square marker. We don't have another pair of angles, so we cannot use AAS.

Cross choice C off the list.

-----------------

We can use SAS because we have two pairs of congruent sides and one pair of congruent angles.

The congruent sides are

  • ED = LK (double tickmarks)
  • DF = KM (single tickmarks)

That takes care of the two "S"s of "SAS". The "A" would be those two right angles which are congruent to one another. The angles are between the congruent sides which is important. Recall that SSA is not a valid congruence theorem.

So that's why choice D is the only answer.

-----------------

Side note: We could use the LL theorem, where L stands for leg, since we are given two pairs of congruent legs for each triangle. Like LA and HA, this only applies to right triangles. LL is a special case of SAS. However, LL isn't listed so we'll just be sticking with SAS as the only answer.

8 0
3 years ago
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