Explanation:
The function is ![f(x)=2 \sin x-2](https://tex.z-dn.net/?f=f%28x%29%3D2%20%5Csin%20x-2)
To plot the function in the graph, first we shall determine the amplitude, period, phase shift and vertical shift.
The function is of the form, ![y=A \sin (B(x+C))+D](https://tex.z-dn.net/?f=y%3DA%20%5Csin%20%28B%28x%2BC%29%29%2BD)
where A is the amplitude = ![|a|](https://tex.z-dn.net/?f=%7Ca%7C)
Period is
,
Phase shift is C,
Vertical shift is D.
Hence, from the function
, we have,
Amplitude = ![A=2](https://tex.z-dn.net/?f=A%3D2)
Period = ![\frac{2 \pi }{B}=\frac{2\pi}{1} =2\pi](https://tex.z-dn.net/?f=%5Cfrac%7B2%20%5Cpi%20%7D%7BB%7D%3D%5Cfrac%7B2%5Cpi%7D%7B1%7D%20%3D2%5Cpi)
Phase shift = 0
Vertical shift = -2
Now, substituting the values for x, we get the corresponding values for y.
For
⇒ ![f(x)=-2](https://tex.z-dn.net/?f=f%28x%29%3D-2)
For
⇒ ![f(x)=0](https://tex.z-dn.net/?f=f%28x%29%3D0)
For
⇒ ![f(x)=-2](https://tex.z-dn.net/?f=f%28x%29%3D-2)
For
⇒ ![f(x)=-4](https://tex.z-dn.net/?f=f%28x%29%3D-4)
For
⇒ ![f(x)=-2](https://tex.z-dn.net/?f=f%28x%29%3D-2)
Hence, plotting these points we get the graph which is attached below:
Now, we shall graph the function ![f(x)=-\cos (2 x)+1](https://tex.z-dn.net/?f=f%28x%29%3D-%5Ccos%20%282%20x%29%2B1)
Similarly, we shall determine the amplitude, period, phase shift and vertical shift.
Amplitude = ![A=1](https://tex.z-dn.net/?f=A%3D1)
Period = ![\frac{2 \pi }{B}=\frac{2\pi}{2} =\pi](https://tex.z-dn.net/?f=%5Cfrac%7B2%20%5Cpi%20%7D%7BB%7D%3D%5Cfrac%7B2%5Cpi%7D%7B2%7D%20%3D%5Cpi)
Phase shift = 0
Vertical shift = 1
Now, substituting the values for x, we get the corresponding values for y in the function ![f(x)=-\cos (2 x)+1](https://tex.z-dn.net/?f=f%28x%29%3D-%5Ccos%20%282%20x%29%2B1)
For
⇒ ![f(x)=0](https://tex.z-dn.net/?f=f%28x%29%3D0)
For
⇒ ![f(x)=1](https://tex.z-dn.net/?f=f%28x%29%3D1)
For
⇒ ![f(x)=2](https://tex.z-dn.net/?f=f%28x%29%3D2)
For
⇒ ![f(x)=1](https://tex.z-dn.net/?f=f%28x%29%3D1)
For
⇒ ![f(x)=0](https://tex.z-dn.net/?f=f%28x%29%3D0)
Hence, plotting these points we get the graph which is attached below:
8 would be the constant but in this situation there is a variable next to it so I’m not sure if it would be considered a constant
20/100 times 12 = 2.40
then, 12 minus 2.40 = <em><u>9.60
~~~~~~~~~~~~~~~or~~~~~~~~~~~~~
</u></em><em><u /></em><u />80/100 times 12 = <em><u>9.60</u></em><em><u /></em><u />
Answer:
140 ft²
Step-by-step explanation:
The figure is composed of a rectangle and a triangle
note triangle has a base = 16 - 12 = 4 ft
Area = area of rectangle + area of triangle
= (16 × 8) + (
× 4 × 6)
= 128 + 12
= 140 ft²
Answer:
y<
−43
/83
but if you want a decimal
-0.518072
Step-by-step explanation: