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lakkis [162]
3 years ago
10

If r(x) = 2 – x2 and w(x) = x – 2, what is the range of (w circle r) (x)?

Mathematics
2 answers:
snow_lady [41]3 years ago
6 0

Answer:

(-\infty, 0)

Step-by-step explanation:

VashaNatasha [74]3 years ago
3 0

Answer:

(-\infty, 0)

Step-by-step explanation:

(w circle r) (x) is the composite function(w of r(x)), that is, w(r(x))[/tex]

We have that:

r(x) = 2 - x^{2}

w(x) = x - 2

Composite function:

w(r(x)) = w(2 - x^{2}} = 2 - x^{2} - 2 = -x^{2}

-x^{2} is a negative parabola with vertex at the original.

So the range(the values that y assumes), is:

(-\infty, 0)

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Choice A

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In each case, each equation has an equation of a line in y = mx + b form equaling another equation of a line in y = mx + b form. If the two sides are equal, it is the same equation, there are infinitely many solutions. If the sides are different, then if the slopes are different, the lines intersect at one point, and there is exactly 1 solution. If the slopes are equal, the lines are parallel, and there is no solution.

(Choice A) -10x-10=-10x-10

In Choice A, both sides of the equation are equal, so there are infinitely many solutions.

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