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klio [65]
2 years ago
11

Hank buys a used car for $7,200 and plans to sell it on his used car lot. What is the price of the car after a markup of 15%?

Mathematics
2 answers:
AysviL [449]2 years ago
6 0

Answer:

8280

Step-by-step explanation:

You would multiply 7200 by .15 and then add it back to 7200.

Alex787 [66]2 years ago
5 0

Answer:

$8280

Step-by-step explanation:

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Ms.Sinnott has 7/12 m of string and she cuts the string into eight pieces how long are the new piece of string
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7/96 m

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7/12 ÷ 8 = 7/96

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2 years ago
Find the range of the given function y = 5x + 2, where x > -2.
andrew-mc [135]

Answer:

Its -3,2,7

Step-by-step explanation:

Simply put, you plug in all values greater than -2. Which is what thst function tells you.

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Read 2 more answers
La probabilidad de que el estudiante A apruebe un examen de MM-100 es 0.6, la probabilidad de que apruebe un estudiante B es 0.4
ivanzaharov [21]

Answer:

0.5 = 50% probabilidad de que apruebe el estudiante B dado que el estudiante A aprueba.

Step-by-step explanation:

La probabilidad condicional :

P(B|A) = \frac{P(A \cap B)}{P(A)}

En el cual:

P(B|A) es la probabilidad de que ocurra el evento B, dado que A sucedió.  

P(A \cap B) es la probabilidad de que ocurran tanto A como B.  

P(A) es la probabilidad de que ocurra A.

En esta pregunta :

Evento A: Estudiante A aprueba.

Evento B: Estudiante B aprueba.

La probabilidad de que el estudiante A apruebe un examen de MM-100 es 0.6

Entonces P(A) = 0.6

La probabilidad de que ambos estudiantes aprueben es 0.3

Entonces P(A \cap B) = 0.3

¿Cual es la probabilidad de que apruebe el estudiante B dado que el estudiante A aprueba.?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.3}{0.6} = 0.5

0.5 = 50% probabilidad de que apruebe el estudiante B dado que el estudiante A aprueba.

6 0
3 years ago
Yesterday, Jake rode his bike 6.6 miles. Today he rode2.4 times as far, how many miles did he ride today?
Paul [167]

Answer:

15.84

Step-by-step explanation:

6.6 × 2.4 = 15.84

he rode 15.84 miles today

3 0
2 years ago
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