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FrozenT [24]
3 years ago
6

With a short time remaining in the​ day, a delivery driver has time to make deliveries at 4 locations among the 7 locations rema

ining. How many different routes are​ possible?
Mathematics
1 answer:
omeli [17]3 years ago
3 0

Answer:

35 different routes

Step-by-step explanation:

The problem of how many different routes are possible if a driver wants to make deliveries at 4 locations among 7 locations is a combination problem.

Combination problems are usually selection problems, of all or part of a set of options, without considering the order in which options are selected.

The number of combinations of n objects taken r at a time is: ⁿCᵣ

So, the number of ways the driver can make deliveries at 4 locations out of 7 locations of given by

⁷C₄ = 35 different ways.

Hence, 35 different routes are possible to make deliveries at 4 locations out of 7 locations.

Hope this Helps!!!

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I would assume you're referring to this test? if so the answer is

a, d and e

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The students in Mr. Wilson's Physics class are making golf ball catapults. The
Mnenie [13.5K]

Answer:

Part a) About 48.6 feet

Part b) About 8.3 feet

Part c) The domain is 0 \leq x \leq 48.6\ ft and the range is 0 \leq y \leq 8.3\ ft

Step-by-step explanation:

we have

y=-0.014x^{2} +0.68x

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

where

x is the ball's  distance from the catapult in feet

y is the flight of the balls in feet

Part a)  How far did the ball fly?

Find the x-intercepts or the roots of the quadratic equation

Remember that

The x-intercept is the value of x when the value of y is equal to zero

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-0.014x^{2} +0.68x=0

so

a=-0.014\\b=0.68\\c=0

substitute in the formula

x=\frac{-0.68(+/-)\sqrt{0.68^{2}-4(-0.014)(0)}} {2(-0.014)}

x=\frac{-0.68(+/-)0.68} {(-0.028)}

x=\frac{-0.68(+)0.68} {(-0.028)}=0

x=\frac{-0.68(-)0.68} {(-0.028)}=48.6\ ft

therefore

The ball flew about 48.6 feet

Part b) How high above the ground did the ball fly?

Find the maximum (vertex)

y=-0.014x^{2} +0.68x

Find out the derivative and equate to zero

0=-0.028x +0.68

Solve for x

0.028x=0.68

x=24.3

<em>Alternative method</em>

To determine the x-coordinate of the vertex, find out the midpoint  between the x-intercepts

x=(0+48.6)/2=24.3\ ft

To determine the y-coordinate of the vertex substitute the value of x in the quadratic equation and solve for y

y=-0.014(24.3)^{2} +0.68(24.3)

y=8.3\ ft

the vertex is the point (24.3,8.3)

therefore

The ball flew above the ground about 8.3 feet

Part c) What is a reasonable domain and range for this function?

we know that

A  reasonable domain is the distance between the two x-intercepts

so

0 \leq x \leq 48.6\ ft

All real numbers greater than or equal to 0 feet and less than or equal to 48.6 feet

A  reasonable range is all real numbers greater than or equal to zero and less than or equal to the y-coordinate of the vertex

so

we have the interval -----> [0,8.3]

0 \leq y \leq 8.3\ ft

All real numbers greater than or equal to 0 feet and less than or equal to 8.3 feet

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Need help ASAP! Question in screenshot
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Answer:

A

Step-by-step explanation:

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Answer: x-0.20x+0.0725x

Step-by-step explanation:

Let x be the price. 20% (0.20) 7.25% (0.0725)

x-0.20x+0.0725x

6 0
3 years ago
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