All categories

3 years ago

Lori wants to distribute 35 peaches equally into baskets. how many baskets does Lori need?

Mathematics

2 answers:

gtnhenbr [62]3 years ago

7 0

7 is your answer let me know if you need help with anything else

iren [92.7K]3 years ago

4 0

7 baskets because 5x7= 35.

You might be interested in

Determine the equation of the graph with the coordinates of (4, -1)

Anon25 [30]

Answer:

The required equation of the graph with the coordinates of (4, -1) will be:

$y=\left(x-4\right)^2-1$

The graph is also attached.

Step-by-step explanation:

Given the coordinates (4, -1)

If we put the coordinate values (4, -1) in the given equations, we determine that only $y=\left(x-4\right)^2-1$ is the valid equation as it satisfies the given coordinate value.

For example, putting (4, -1) in the equation

$y=\left(x-4\right)^2-1$

$\left(-1\right)=\left(4-4\right)^2-1$

$-1=\left(0\right)^2-1$

$-1=0-1$

$-1=-1$

So, the equation $y=\left(x-4\right)^2-1$ is true for the coordinate values (4, -1).

Therefore, the required equation of the graph with the coordinates of (4, -1) will be:

$y=\left(x-4\right)^2-1$

Please check, the graph is also attached.

3 0

2 years ago

What is the value of x?

LenaWriter [7]

Answer:

1.33

Step-by-step explanation:

4 0

2 years ago

The graph shows Ms. Padilla's monthly cell phone cost, where x is the number of minutes she uses the phone during the month.

balu736 [363]

Answer: the X intercept mean this here

Ms.

Padilla is charged $0.04/min.

Ms. Padilla pays $16 for months she makes 0 min of calls

Step-by-step explanation:

7 0

11 months ago

If log2 5 = k, determine an expression for log32 5 in terms of k.

lukranit [14]

Answer:

$log_3_2(5)=\frac{1}{5} k$

Step-by-step explanation:

Let's start by using change of base property:

$log_b(x)=\frac{log_a(x)}{log_a(b)}$

So, for $log_2(5)$

$log_2(5)=k=\frac{log(5)}{log(2)}\hspace{10}(1)$

Now, using change of base for $log_3_2(5)$

$log_3_2(5)=\frac{log(5)}{log(32)}$

You can express $32$ as:

$2^5$

Using reduction of power property:

$log_z(x^y)=ylog_z(x)$

$log(32)=log(2^5)=5log(2)$

Therefore:

$log_3_2(5)=\frac{log(5)}{5*log(2)}=\frac{1}{5} \frac{log(5)}{log(2)}\hspace{10}(2)$

As you can see the only difference between (1) and (2) is the coefficient $\frac{1}{5}$ :

So:

$\frac{log(5)}{log(2)} =k\\$

$log_3_2(5)=\frac{1}{5} \frac{log(5)}{log(2)} =\frac{1}{5} k$

6 0

2 years ago

Explain why lxl=-5 doesn't have a solution

igomit [66]

It doesn’t have a value. The absolute value function is always positive or 0

3 0

3 years ago

Read 2 more answers