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dlinn [17]
3 years ago
12

How much are 6 of these $40’s

Mathematics
1 answer:
Kisachek [45]3 years ago
5 0

Answer:

$240

Step-by-step explanation:

there are 6 sets of 2 $20's which make $40, so you'd multiply 40 by 6 them you'd get $240

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Let X denote a random variable which corresponds to the number of players in a team who get injured during a game. If we assume
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Answer:

(a)

The values of X can be 0, 1, 2 , ..., 10 . So, X is a discrete random variable.

(b)

The distribution of X is Binomial distribution with the parameters n = 10 and p = 0.2

(c)

Probability that no one or one person will be injured = P(X = 0) + P(X = 1)

= 10C0 * 0.20 * (1 - 0.2)10-0 + 10C1 * 0.21 * (1 - 0.2)10-1

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(d)

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(e)

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(f)

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= 9! / ((9-1)! 1!)

= 9

Probability that the best player got injured = Number of ways in which 1 people gets out of 9 and best person gets injured / Number of ways in which 2 people gets injured

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Step-by-step explanation:

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Step-by-step explanation:

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