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Slav-nsk [51]
3 years ago
5

Ibuki factored 12x^7as (4x^3)(3x^4)

Mathematics
1 answer:
Marina86 [1]3 years ago
8 0

Answer:

Both are correct.

Step-by-step explanation:

The key understanding here is that you can factor a monomial in many different ways!

To check if any of the factorizations is correct, we can multiply the factors and see if their product is really 12x^712x

7

12, x, start superscript, 7, end superscript.

Hint #22 / 4

\begin{aligned} (\blueD{4}\maroonD{x^3})(\blueD{3}\maroonD{x^4})&=(\blueD{4})(\blueD{3})(\maroonD{x^3})(\maroonD{x^4}) \\\\ &=\blueD{12}\maroonD{x^7} \end{aligned}

(4x

3

)(3x

4

)

​

 

=(4)(3)(x

3

)(x

4

)

=12x

7

​

So Ibuki is correct!

Hint #33 / 4

\begin{aligned} (\blueD{2}\maroonD{x^6})(\blueD{6}\maroonD{x})&=(\blueD{2})(\blueD{6})(\maroonD{x^6})(\maroonD{x}) \\\\ &=\blueD{12}\maroonD{x^7} \end{aligned}

(2x

6

)(6x)

​

 

=(2)(6)(x

6

)(x)

=12x

7

​

So Melodie is also correct!

Both Ibuki and Melodie are correct.

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I need help on question 2 i need the simplified answer and the restrictions
Anastaziya [24]

Answer:

x cannot be 5 or -3.

\frac{x+5}{x+3}

Step-by-step explanation:

The restrictions for a fraction is that the bottom cannot be 0.

So if we find when the bottom is 0 we have found the values that x cannot be.

Let's solve x^2-2x-15=0.

Since the coefficient of x^2 is 1 all we have to do is find two numbers whose product is -15 and whose sum is -2.

Those numbers are -5 and 3 since (-5)(3)=-15 and (-5)+(3)=-2.

So the factored form of the equation is:

(x-5)(x+3)=0

This means either x-5=0 or x+3=0.

We do have to solve both.

x-5=0 can be solved by adding 5 on both sides.

x-5+5=0+5

x+0=0+5

x=5

x+3=0 can be solved by subtracting 3 on both sides.

x+3-3=0-3

x+0=0-3

x=-3

So x can be any number except x=5 or x=-3.

We already factored the bottom as (x-5)(x+3).

The top is a difference of squares, x^2-a^2,

which can be factored as (x-a)(x+a).

So the top factors as (x-5)(x+5).

The fraction can then be written as:

\frac{x^2-25}{x^2-2x-15}=\frac{(x-5)(x+5)}{(x-5)(x+3)}

This can further simplified assuming x is not 5 we can write it as \frac{x+5}{x+3}.  I canceled the common factor of (x-5).

5 0
3 years ago
Given that the measure of angle 6 is 1/8 of measure of angle 4. Find the measures of these two angles if a∥b.
vredina [299]

Answer:

see explanation

Step-by-step explanation:

Let ∠4 be x then ∠6 is \frac{1}{8} x

∠4 and ∠6 are same side interior angles and are supplementary, thus

x + \frac{1}{8}x = 180

Multiply through by 8 to clear the fraction

8x + x = 1440, that is

9x = 1440 ( divide both sides by 9 )

x = 160

Hence ∠4 = 160° and ∠6 = 160° ÷ 8 = 20°

8 0
2 years ago
Read 2 more answers
I need help with this question
lina2011 [118]
Ratio: 3/4 : 1/2

We can also write this as:

3/4 / 1/2

Flip the 2nd fraction and multiply:

3/4 * 2/1

Multiply the numerators and denominators together:

6/4

Simplify:

3/2
8 0
3 years ago
Read 2 more answers
PLEASE HELP ME SOMEONE
Anna71 [15]

Answer:

D. 44 cubic inches

Step-by-step explanation:

If I need an explanation I'll be happy to comment it to you.

Hope this helped otherwise!!!

5 0
2 years ago
Let f(x) = x + 8 and g(x) = x2 - 6x - 7. Find f(g(2)).
Alex
We are given with two functions: f(x) = x + 8 and g(x) = x2 - 6x - 7. In this problem, the value of f(g(2)) is asked. We first substitute g(x) to f(x) resulting to f(x2 - 6x - 7) = x2 - 6x - 7 + 8 = x2 - 6x  + 1. If x is equal to 2, then <span>f(g(2)) = 2^</span>2 - 6*2  + 1 equal to -7.
6 0
3 years ago
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