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3 years ago

Ibuki factored 12x^7as (4x^3)(3x^4)

Mathematics

1 answer:

Marina86 [1]3 years ago

8 0

Answer:

Both are correct.

Step-by-step explanation:

The key understanding here is that you can factor a monomial in many different ways!

To check if any of the factorizations is correct, we can multiply the factors and see if their product is really 12x^712x

12, x, start superscript, 7, end superscript.

Hint #22 / 4

\begin{aligned} (\blueD{4}\maroonD{x^3})(\blueD{3}\maroonD{x^4})&=(\blueD{4})(\blueD{3})(\maroonD{x^3})(\maroonD{x^4}) \\\\ &=\blueD{12}\maroonD{x^7} \end{aligned}

(4x

)(3x

)

=(4)(3)(x

)(x

)

=12x

So Ibuki is correct!

Hint #33 / 4

\begin{aligned} (\blueD{2}\maroonD{x^6})(\blueD{6}\maroonD{x})&=(\blueD{2})(\blueD{6})(\maroonD{x^6})(\maroonD{x}) \\\\ &=\blueD{12}\maroonD{x^7} \end{aligned}

(2x

)(6x)

=(2)(6)(x

)(x)

=12x

So Melodie is also correct!

Both Ibuki and Melodie are correct.

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The radius is 20. what's the length of arc AB?

AURORKA [14]

Answer:yyghvggft

Step-by-step explanation:

3 0

3 years ago

Mary wants to find this product. 58 x 20 How can Mary find the product? A. 0 +16 + 100 B. 0 + 160 + 1000 . C. 58 + 16 + 100 D. 5

Fittoniya [83]

Answer:

Step-by-step explanation:

58×20=1160

0+160+1000=1160

8 0

3 years ago

Two boys and three girls are auditioning to play the piano for a school production. Two students will be chosen, one as the pian

Sergio039 [100]

The answer is 0.24

To calculate this, a multiplication rule is used. The multiplication rule calculates the probability that both of two events will occur. In this method, the probabilities of each event are multiplied. Here we have two events:

1. The probability that the pianist will be a boy,

2. The probability that the alternate will be a girl.

So, let's calculate these probabilities:

There are in total 5 children:

2 boys + 3 girls = 5 children.

1. The probability that the pianist will be a boy is 2 boys out of 5 children, which is 2/5.

2. The probability that the alternate will be a girl is 3 girls out of 5 children, which is 3/5.

The probability that the pianist will be a boy and the alternate will be a girl is:

2/5 × 3/5 = 6/25

6/25 × 4/4 = 24/100 = 0.24

3 0

3 years ago

Read 2 more answers

An island is 1 mi due north of its closest point along a straight shoreline. A visitor is staying at a cabin on the shore that i

Elanso [62]

Answer:

The visitor should run approximately 14.96 mile to minimize the time it takes to reach the island

Step-by-step explanation:

From the question, we have;

The distance of the island from the shoreline = 1 mile

The distance the person is staying from the point on the shoreline = 15 mile

The rate at which the visitor runs = 6 mph

The rate at which the visitor swims = 2.5 mph

Let 'x' represent the distance the person runs, we have;

The distance to swim = $\sqrt{(15-x)^2+1^2}$

The total time, 't', is given as follows;

$t = \dfrac{x}{6} +\dfrac{\sqrt{(15-x)^2+1^2}}{2.5}$

The minimum value of 't' is found by differentiating with an online tool, as follows;

$\dfrac{dt}{dx} = \dfrac{d\left(\dfrac{x}{6} +\dfrac{\sqrt{(15-x)^2+1^2}}{2.5}\right)}{dx} = \dfrac{1}{6} -\dfrac{6 - 0.4\cdot x}{\sqrt{x^2-30\cdot x +226} }$

At the maximum/minimum point, we have;

$\dfrac{1}{6} -\dfrac{6 - 0.4\cdot x}{\sqrt{x^2-30\cdot x +226} } = 0$

Simplifying, with a graphing calculator, we get;

-4.72·x² + 142·x - 1,070 = 0

From which we also get x ≈ 15.04 and x ≈ 0.64956

x ≈ 15.04 mile

Therefore, given that 15.04 mi is 0.04 mi after the point, the distance he should run = 15 mi - 0.04 mi ≈ 14.96 mi

$t = \dfrac{14.96}{6} +\dfrac{\sqrt{(15-14.96)^2+1^2}}{2.5} \approx 2..89$

Therefore, the distance to run, x ≈ 14.96 mile

6 0

3 years ago

A baby weighed 7.25 pounds at birth. At the end of 8 months, the baby weighed 212

Vinil7 [7]

Answer:

1537pounds

Step-by-step explanation:

Given parameters:

Weight of baby at birth = 7.25 pounds

Unknown:

Weight at the end of 8months = ?

Solution:

From the second sentence;

Weight at the end of the eighth month = 212 x weight at birth.

Input the parameters and solve;

Weight at the end of eighth month = 212 x 7.25 = 1537pounds

7 0

3 years ago