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Leviafan [203]
3 years ago
10

Write the equation of the line given the slope and the y-intercept. Type your answer in the box without skipping any spaces. m =

2, y-intercept (0, 3)
Mathematics
1 answer:
Over [174]3 years ago
7 0

The equation of a line given the slope and y-intercept is given as;

             m(x-x₁) = (y-y₁)

∴equation of line with m = 2 and y-intercept = (0,3) =

     2(x - 0) = (y - 3)

 = 2x - 0 = y - 3

  making y the subject obtains y = 2x + 3.

so, equation of the line: y = 2x + 3.

 

  

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Jerry has been learning to multiply decimals by Integers.
Bogdan [553]

Answer:

Yes

Step-by-step explanation:

Multiplying an integer by 0.01 is the same as Dividing such as :

0.01 = 10^-2

100= 10

For instance :

A number, n = 5 is multiplied by 10^-2

5 * 0.01 = 0.05

Thus, divide the number, n by 100;

5 / 100 = 0.05

Hence, the proof.

7 0
3 years ago
In triangle A B C, which angle is the included angle between segment A B and segment B C?
Papessa [141]

Answer:

c

Step-by-step explanation:

4 0
3 years ago
AC−⇀− bisects ∠BAD.If m∠BAC=38°, find the m∠BAD.
PilotLPTM [1.2K]

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Step-by-step explanation:

4 0
3 years ago
∆ABC is an isosceles triangle. The length of CB is 12 feet 4 inches and the congruent sides are
son4ous [18]

Answer:

Answer for 2nd is option c, for 3rd is option d, for 4th is option e

Step-by-step explanation:

As we know 1 ft.=12 in.

  1. In ΔABC

   ∴ The congruent sides are AB and AC respectively

  • CB =12 ft. 4 in.=148 in.
  • AB=\frac{3}{4}CB =111 in. =9 ft. 3 in.
  • AC=\frac{3}{4}CB =111 in. =9 ft. 3 in.

    ∵  <em>Perimeter of ΔABC</em> =AB+AC+CB

                                        =9 ft. 3 in. + 9 ft. 3 in. +12 ft. 4 in.

                                        =30 ft. 10 in.

    2. In ΔDEF

    ∴ The congruent sides are DE and DF respectively

  • DE =  6 ft. 3 in. =75 in.
  • DF =  6 ft. 3 in. =75 in.
  • Let the length of FE is equal to x
  • 0.75FE =DE =DF
  • 0.75x = 6 ft. 3 in. =75 in.
  • x =100 in. =8 ft. 4 in.

   ∵ <em>Perimeter of ΔDEF</em> =DE+DF+FE

                                        = 6 ft. 3 in. +6 ft. 3 in. +8 ft. 4 in.

                                        = 20 ft. 10 in.

    3. In ΔJKL

    ∴ The congruent sides are JL and KL respectively

  • JK = x+3
  • KL =4x-17
  • JL  =6x-45
  • JL≅KL
  • 4x-17 =6x-45  . . . . . . . . . . . . . . . . . . . . . . . (1)
  • Subracting 4x from both sides from eq 1
  • -17 =2x-45
  • Adding 45 on both the sides
  • 28 =2x
  • Dividing by 2 on both sides
  • 14 =x
  • JK = 14+3 =17
  • KL = 4×14-17 =39
  • JL = 6×14-45 =39

   ∵ <em>The dimensions of the ΔJKL are 39,39 and 17.</em>

6 0
4 years ago
P=q+2 2p+3q=-26 <br> help
kompoz [17]
All you have to do is plug and solve...

2(q+2) + 3q = -26
2q + 4 + 3q = -26

Subtract 4 from the left side and move it to the right...

 2q + 4 + 3q = -26
       - 4            - 04
_________________
2q + 3q = -30

Now add 3q and 2q together and you get 5q, next divide...

5q = -30
_______
5         5

Finally, you get q equal to negative 6 (-6)!
3 0
3 years ago
Read 2 more answers
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