This is a neat little question. I don't think I've seen it before.
Step one
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Find c
3^2 + 4^2 = c^2
9 + 16 = c^2
c^2 = 25
c = 5
Step 2
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Set up your first equation for b^2
a^2 + 4^2 = b^2 from triangle XWY
Step 3
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Set up your second equation for b^2
25 +b^2 = (a + 3)^2 from triangle XWZ
Step 4
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Put the results of Step 2 into step 3 and solve
25 + a^2 + 16 = (a + 3)^2 Collect the like terms on the left.
41 + a^2 = (a + 3)^2 Expand the brackets on the right
41 + a^2 = a^2 + 6a + 9 Transfer the 9 to the left.
32 + a^2 = a^2 + 6a Subtract a^2 from both sides.
6a = 32 Divide by 6
a = 32 / 6
a = 5 2/6
a = 5 1/3
Answer:
y=-3x2 - 12x+6
, x = -(-12)/2*3 = 2 this one has axis of symmetry x = 2
Step-by-step explanation:
y = 3x² + 12x+6 : x = -12/6 = -2
y = 3x2 - 6x+12
, x = -(-6)/2*3 = -1
y=-3x2 - 12x+6
, x = -(-12)/2*3 = 2 this one
y=-3x2 + 12x+6 , x = -12/2*3 = -2
The answer is approx. 18.33 there are more decimals in actuality. I used a calculator, but a good strategy for numbers with square roots that aren’t integers is to find numbers with easier SR that are less and greater than the number and then estimate
Answer:
the first one and the second one not the third one
Answer:
Maybe show a picture?
Step-by-step explanation:
