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3 years ago

How can the equation of a parabola be derived when given the focus and the directrix

1 answer:

7 0

If the focus of a parabola is and the directrix is , find theequation of the parabola. Let ( x 0 , y 0 ) be any point on theparabola. Find the distance between ( x 0 , y 0 ) and the focus. Then find the distance between ( x 0 , y 0 ) and directrix.

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What is the ratio 1:3 when turned into a fraction?

Anika [276]

If you turn the ratio 1:3 into a fraction it would be 1 over 3 I hope this helps

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3 years ago

A basic cellular phone plan costs $4 per month for 70 calling minutes. Additional time costs $0.10 per minute. The formula C= 4+

Harrizon [31]

Answer:

For a monthly cost of at least $7 and at most $8, you can have between 100 and 110 calling minutes.

Step-by-step explanation:

The problem states that the monthly cost of a celular plan is modeled by the following function:

$C(x) = 4 + 0.10(x-70)$

In which C(x) is the monthly cost and x is the number of calling minutes.

How many calling minutes are needed for a monthly cost of at least $7?

This can be solved by the following inequality:

$C(x) \geq 7$

$4 + 0.10(x - 70) \geq 7$

$4 + 0.10x - 7 \geq 7$

$0.10x \geq 10$

$x \geq \frac{10}{0.1}$

$x \geq 100$

For a monthly cost of at least $7, you need to have at least 100 calling minutes.

How many calling minutes are needed for a monthly cost of at most 8:

$C(x) \leq 8$

$4 + 0.10(x - 70) \leq 8$

$4 + 0.10x - 7 \leq 8$

$0.10x \leq 11$

$x \leq \frac{11}{0.1}$

$x \leq 110$

For a monthly cost of at most $8, you need to have at most 110 calling minutes.

For a monthly cost of at least $7 and at most $8, you can have between 100 and 110 calling minutes.

8 0

3 years ago

Boris drove 240 miles using 9 gallons of gas. At this rate, how many gallons of gas would he need to drive 216 miles?

satela [25.4K]

Use proportion to solve this.
240 miles needs 9 gallons
216 miles needs (9÷240) × 216 = 8.1 gallons

Hope it helped!

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3 years ago

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Ksivusya [100]

If you were asking for how many packages you would like if each you would want one pack of crackers, and two packages of cheese. Simple math. The reason why you get that answer and that equation/solution, is by simply make ing the cheese grater then the crackers, but if the cheese is lower then the crackers, you get more cheese packages because then you get two times the cheese and you will have enough cheese for all the crackers. You may have a little bit of cheese left, but who doesn't like it plain? That is the answer.

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3 years ago

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Rama09 [41]

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3 years ago

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