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Furkat [3]
3 years ago
15

What is 4÷92=,6÷58= in axon math

Mathematics
1 answer:
xeze [42]3 years ago
6 0
Its 28=9.67 bar i believe
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Complete the paragraph to show how you can solve problems involving equivalent expressions.
miv72 [106K]

Answer:

Step-by-step explanation:

Model the expressions

with bar models or algebra tiles to determine if the expressions are

Equivalent.

You can also write equivalent expressions using

properties of operations

and order of operations.

8 0
2 years ago
Read 2 more answers
Consider the quadratic equation x2=4x-5. How many solutions does the equation have
Norma-Jean [14]
The quadratic formula is =(-b+-sqrt(b^2-4ac))/2a
as you notice the term under the square root is b^2-4ac if it is postive then the equation clearly will have two real soultions if it is negative then the equation will have two imaginary soultion if it is zero then the the equation will have one soultion
so let us calculate b^2-4ac for our given equation
x^2=4x-5 so let us write it in general form which is ax^2+bx+c=0
subtracting 4x from both sides
x^2-4x=-5
adding 5 to both sides
x^2-4x+5=0
a=1,b=-4,c=5
b^2-4ac=(-4)^2-4(1)(5)=16-20=-4
which means the equation has two imaginary soultions
3 0
3 years ago
Read 2 more answers
Determine if the expression 3c^5+7c^-1-c is a polynomial or not. If it is a polynomial, state the type and degree of the polynom
ludmilkaskok [199]

Answer: It's not a polynomial

It's not a polynomial because the exponent of -1 in the second term. The exponents for any polynomial must be nonnegative whole numbers {0,1,2,3,...}

3 0
2 years ago
Geometry question!!
Mademuasel [1]

Answer:

GQ=25 units

Step-by-step explanation:

we know that

Point Q is the midpoint of GH

so

GH=GQ+QH  and  GQ=QH

GH=2GQ -------> equation A

we have

GH=5x-5

GQ=2x+3

substitute in the equation A and solve for x

5x-5=2(2x+3)

5x-5=4x+6

5x-4x=6+5

x=11

Find the length of GQ

GQ=2x+3

substitute the value of x

GQ=2(11)+3

GQ=25 units

4 0
3 years ago
IXL geometry please help!
Sedaia [141]
<h3>Answer: 32 degrees</h3>

================================

Work Shown:

Inscribed angle theorem

arc measure = 2*(inscribed angle)

arc ABC = 2*(angle D)

arc ABC = 2*(35)

arc ABC = 70 degrees

-------------

break arc ABC into its smaller pieces

(minor arc AB)+(minor arc BC) = arc ABC

(38)+(minor arc BC) = 70

minor arc BC = 70-38

minor arc BC = 32

8 0
3 years ago
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