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Talja [164]
3 years ago
13

Two objects in outer space drift apart at an average rate of 25 kilometers every year. If the objects continue to drift apart fr

om each other at the same rate, how many kilometers will they drift in 10 years?
Mathematics
1 answer:
ivanzaharov [21]3 years ago
4 0
In 10 years they would drift apart 250 kilometers.
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Can I get help with this​
MrRissso [65]

Answer:

2p+1d+2t+1d+2t+1p+2t+1d

3p+3d+6t

Step-by-step explanation:

2p+1d+2t+1d+2t+1p+2t+1d

3p+3d+6t

7 0
3 years ago
A family has annual loan payments equal to 32% of their annual income. During the year, the loan payments total $15,680. What is
slavikrds [6]

let family income be x

32%x=15680

32/100x=15680

x=15680X100/32

x=49000

6 0
3 years ago
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Find the arc length of the semicircle.
mafiozo [28]

The arc length of the semicircle is 15.7

<h3>Calculating Arc length </h3>

From the question, we are to determine the arc length of the semicircle

Arc length can be determined by using the formula,

Arc length = θ/360° × 2πr

Where θ is the angle subtended by the arc

and r is the radius of the circle

In the given diagram,

θ = 180°

and r = 10/2

r = 5

Thus,

The arc length of the semicircle = 180°/360° ×2×3.14×5

The arc length of the semicircle = 1/2×2×3.14×5

The arc length of the semicircle = 15.7

Hence, the arc length of the semicircle is 15.7

Learn more on Calculating Arc length here: brainly.com/question/16552139

#SPJ1

8 0
2 years ago
Rewrite the equation -30x + 2y- 100=0
Black_prince [1.1K]
Rewritten: y=15x + 50
slope: 15
y intercept: (0,50)
7 0
3 years ago
Solve please:<br><br> 1/5 (25-5a) = 4-a
Liono4ka [1.6K]

Answer: There is no solution.

Step-by-step explanation:

1.) 1 / 5 (25) + 1 / 5 (-5a) = 4 - a

2.) 5 - a = 4 - a

3.) 5 - a + a = 4 - a + a

4.) 5 = 4

The variable a is completely removed, leaving the final answer as 5 = 4, which isn't true.

8 0
4 years ago
Read 2 more answers
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