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Olin [163]
3 years ago
15

1. A student conducted research about the roles of molecules in metabolic processes

Biology
1 answer:
Vlada [557]3 years ago
5 0

Answer:

Enzyme- Peptidase/protease

Explanation:

According to this question, a student is conducting an experiment to determine the roles of molecules in metabolic processes such as digestion. Based on what she found out that the molecule, which itself can be broken down into amino acids, can also break down proteins into amino acids, this suggests that the molecule being described is a PROTEOLYTIC ENZYME.

This is because an enzyme is made up of proteins which can be denatured or broken down into its simplest unit (amino acids) and also, a substance that breaks down amino acid is said to be PROTEOLYTIC.

However, another observation that the molecule is found in high concentrations in the small intestine was made, hence, the enzyme is a PEPTIDASE OR PROTEASE, which are secreted into the small intestine by the pancreas to aid digestion of proteins.

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Cystic fibrosis is most common in individuals of Northern European descent, affecting 1 in 3200 newborns. Assuming that these al
IgorLugansk [536]

Answer:

0.0177

Explanation:

Cystic fibrosis is an autosomal recessive disease, thereby an individual must have both copies of the CFTR mutant alleles to have this disease. The Hardy-Weinberg equilibrium states that p² + 2pq + q² = 1, where p² represents the frequency of the homo-zygous dominant genotype (normal phenotype), q² represents the frequency of the homo-zygous recessive genotype (cystic fibrosis phenotype), and 2pq represents the frequency of the heterozygous genotype (individuals that carry one copy of the CFTR mutant allele). Moreover, under Hardy-Weinberg equilibrium, the sum of the dominant 'p' allele frequency and the recessive 'q' allele frequency is equal to 1. In this case, we can observe that the frequency of the homo-zygous recessive condition for cystic fibrosis (q²) is 1/3200. In consequence, the frequency of the recessive allele for cystic fibrosis can be calculated as follows:

1/3200 = q² (have two CFTR mutant alleles) >>  

q = √ (1/3200) = 1/56.57 >>

- Frequency of the CFTR allele q = 1/56.57 = 0.0177  

- Frequency of the dominant 'normal' allele p = 1 - q = 1 - 0.0177 = 0.9823

4 0
3 years ago
There are no fossils of mammals in the oldest layers of rock. What
mrs_skeptik [129]

Answer:

They were not around at that time or either from it being so hot they just disappeared/melted.

Explanation:

3 0
3 years ago
Read 2 more answers
What needs to happen to DNA for cells to divide
torisob [31]

Answer:

each new cell needs a DNA copy, which serves as instructions on how to function as a cell. DNA replicates before a cell divides. The replication process is semi-conservative, which means that when DNA creates a copy, half of the old strand is retained in the new strand to reduce the number of copy errors.

Explanation:

8 0
4 years ago
Bears are known to hibernate during the winter and give birth to their cubs 1 point
damaskus [11]

Answer:

ufuddsiodpfofiffopOI

Explanation:

3 0
3 years ago
I need help figuring this out. Please
defon

Answer:

1) G C G U A U G (C C C) (U U U) (A A C) (C G C)

2) U U A U G (C G U) (U A G) (G C G) (U U U) (A U U)

3) U A U G (G C U) (U A G)  (A A U) (A A C) (C C G) (U A A)

4) U U A U G (C A A) (A G G) (G C G) (U A U) (C U U) (U A G)

5) represent codons which are groupings of 3 consecutive nucletides

Explanation:

Opposites for REGULAR mDNA base pairings are T= A  and G = C, however, since it is mRNA, your base pairings change a little. G is still to C BUT Thymine (T) becomes Uracil (U) so A= U instead of A= T.  So big difference between mRNA and mDNA is that Thymine changes to Uracil and vice versa depending on how the code is being translated.

Hope this helps some, please let me know if there's anything that doesn't make sense

8 0
3 years ago
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