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Greeley [361]
3 years ago
6

A pump can fill a swimming pool in 8 hours. The pool also has a drain that can empty the pool in 10 hours. If someone turns on t

he pump to fill the pool, but forgets to shut the drain, how long would it take for the pool to fill?
Mathematics
1 answer:
cluponka [151]3 years ago
7 0

Answer:

40 hours will it take for the pool to fill.

Step-by-step explanation:

A pump can fill a swimming pool in 8 hours.

Work done by pump to fill in 1 hour is  \frac{1}{8}

The pool also has a drain that can empty the pool in 10 hours.

Work done by pump to drain in 1 hour is  \frac{1}{10}

If someone turns on the pump to fill the pool, but forgets to shut the drain.

Work done by both pipe in 1 hour is

W=\frac{1}{8}-\frac{1}{10}

W=\frac{10-8}{80}

W=\frac{2}{80}

W=\frac{1}{40}

Both pipe filled \frac{1}{40} part of pool in hours = 1

Both pipe filled complete pool in hours = \frac{1}{\frac{1}{40}}=40

Therefore, 40 hours will it take for the pool to fill.

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The center of a circle is at (-2, 3) and point (4,6) is on its circumference.
Lostsunrise [7]

Answer: i don’t know

Step-by-step explanation:

yes

8 0
3 years ago
The line 10x + py = q is a tangent at the point (5, 4) in another circle with centre
Monica [59]

Answer:

  (p, q) = (8, 82)

Step-by-step explanation:

When a circle is centered at the origin, the radius to point (a, b) will have slope m = b/a. The tangent is perpendicular to the radius, so the tangent at point (a, b) will have slope -a/b. In point-slope form, the equation of the tangent line will be ...

  y -k = m(x -h) . . . . . point-slope equation of line with slope m through (h, k)

  y -b = (-a/b)(x -a)

Rearranging this to standard form, we have ...

  b(y -b) = -a(x -a)

  by -b² = -ax +a²

  ax +by = a² +b²

__

For (a, b) = (5, 4), the standard form equation of the tangent can be written ...

  5x +4y = 5² +4² = 41

Your given equation has an x-coefficient that is twice the value shown in this equation, so we need to multiply this equation by 2:

  2(5x +4y) = 2(41)

  10x +8y = 82

Comparing to 10x +py = q, we see that ...

 p = 8

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4 0
2 years ago
Graph the line.<br><br><br> y = −4x + 2
MrRissso [65]

Answer:

it rise over run so put 2y on graph count down 4 and move right 1

Step-by-step explanation:

8 0
3 years ago
Find a parametric representation for the part of the cylinder y2 + z2 = 49 that lies between the planes x = 0 and x = 1. x = u y
sweet-ann [11.9K]

Answer:

The equation for z for the parametric representation is  z = 7 \sin (v) and the interval for u is 0\le u\le 1.

Step-by-step explanation:

You have the full question but due lack of spacing it looks incomplete, thus the full question with spacing is:

Find a parametric representation for the part of the cylinder y^2+z^2 = 49, that lies between the places x = 0 and x = 1.

x=u\\ y= 7 \cos(v)\\z=? \\ 0\le v\le 2\pi \\ ?\le u\le ?

Thus the goal of the exercise is to complete the parameterization and find the equation for z and complete the interval for u

Interval for u

Since x goes from 0 to 1, and if x = u, we can write the interval as

0\le u\le 1

Equation for z.

Replacing the given equation for the parameterization y = 7 \cos(v) on the given equation for the cylinder give us

(7 \cos(v))^2 +z^2 = 49 \\ 49 \cos^2 (v)+z^2 = 49

Solving for z, by moving 49 \cos^2 (v) to the other side

z^2 = 49-49 \cos^2 (v)

Factoring

z^2 = 49(1- \cos^2 (v))

So then we can apply Pythagorean Theorem:

\sin^2(v)+\cos^2(v) =1

And solving for sine from the theorem.

\sin^2(v) = 1-\cos^2(v)

Thus replacing on the exercise we get

z^2 = 49\sin^2 (v)

So we can take the square root of both sides and we get

z = 7 \sin (v)

4 0
3 years ago
What are the zeros for both functions
sammy [17]

Answer:

the zero of a function is the value of x which makes the final value zero

First Equation:

So let 25 - 2x equal to 0

<em>25 - 2x = 0</em>

x = 12.5

Second Equation:

Let 2x² - 11x - 6 equal to zero

<em>2x² - 11x - 6 = 0 </em>

<em>2x² - 12x + x - 6 = 0 </em><em>(Splitting the middle term)</em>

<em>2x(x - 6) + 1(x - 6) = 0</em>

<em>(2x + 1) (x - 6) = 0</em>

So we can transpose either one of the brackets below the zero

(2x + 1) = 0                 or             (x-6) = 0

x = -1/2                      or             x = 6

5 0
3 years ago
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