A regular octagon has what type of symmetry?
2 answers:
You might be interested in
Answer:
Step-by-step explanation:
A function satisfying the equation is said to be an even function. This denomination comes from the fact that the same relation is satisfied for functions of the form
with
even. Observe that if
is twice differentiable we can derivate using the chaing rule as follows:
implies
Applying the chain rule again we have:
implies
So we have that function is also an even function.
Answer:
See attachment below
Step-by-step explanation:
For the first option, we are given m = - 2 / 3, b = 3. This is likely in the point - slope form y = mx + b, where m = slope and b = y - intercept. Thus, the equation of the line in point - slope form given this information, should be y = - 2 / 3x + 3. It seems as if none of the following equations match this form, so let us interchange the equation a bit,
y = - 2 / 3x + 3,
y + 2 / 3x = 3,
2x + 3y = 9 - Option C
_______________________________________________________
Next we are given m = - 3 / 2, and that this line passes through the point ( 4, - 1 ). Substitute m as - 3 / 2, x as 4, y as - 1, knowing point ( 4, - 1 ), into the form y = mx + b - solving for b.
- 1 = ( - 3 / 2 )( 4 ) + b,
b = 5,
Thus the equation in point - slope form should be y = - 3 / 2x + 5. None of the choices match this, so let us again alter the equation,
y = - 3 / 2x + 5,
2y = - 3x + 10,
- 2y = 3x - 10 - Option A
_______________________________________________________
( 6, 3 ) and ( 3, 1 ) is given to lie on this line. The slope of the line should be as follows,
Slope = 3 - 1 / 6 - 3 = 2 / 3
Now let us determine the y - intercept ( b ) by substitute one of the points, say ( 6, 3 ). In this case x = 6, and y = 3,
3 = ( 2 / 3 )( 6 ) + b,
b = - 1,
y = 2 / 3x - 1 = Option D
Take a look at the attachment below for further help;
