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Volgvan
3 years ago
10

Gary had a 40% discount for car speakers. The sale price of the speakers was $96.25. What was the original price of the speakers

? Round to the nearest cent.
Mathematics
1 answer:
Ostrovityanka [42]3 years ago
5 0

Answer:

Step-by-step explanation:

If the price after the discount is subtracted is $96.25 then this is what you do

u times 0.40 x 96.25 which is 38.5 so since you are wanting to know what the price was before the discount you would add 38.5 to 96.25 and when you do that your answer is 134.75

but if you are just trying to get the discount from 96.25 you subtract 38.5 from 96.25

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Identify the x-intercepts of the function below f(x)=x^2+12x+24
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<u>ANSWER:  </u>

x-intercepts of  \mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})

<u>SOLUTION:</u>

Given, f(x)=x^{2}+12 x+24 -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

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Here, for (1) a = 1, b= 12 and c = 24

X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}

\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}

Hence the x-intercepts of  \mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})

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