Answer:
4/42 = 2/21 when simplified down
Step-by-step explanation:
Cancel the common factor: 2
=2/21
Answer:
The correct evaluation is 1 1/3 (one and one-third) and not 16 and one-third
Step-by-step explanation:
The student was wrong in his evaluation because the correct result should be 1 1/3 (one and one-third) and not 16 and one-third
The expression '1/3 more than the product of four and a number' means
(4g + 1/3)
Evaluating the expression when g = 1/4
You will have
4×1/4 + 1/3
= 1/1 + 1/3
Find the LCM of 1 and 3 and add
= (3+1)/3
=4/3
= 1 1/3
The correct evaluation is 1 1/3 (one and one-third) and not 16 and one-third
Area would be 4.52 A= pi x radius squared
Circumference would be 7.54 C= 2 pi radius. Hope that makes sense.
The formula for perimeter is P = 2length + 2width (P = 2L + 2W)
You know that the length is 4 more yards then twice the width. In equation form this would be:
length = 4 + 2w
Plug what you know into the perimeter formula:
26 = 2(4 + 2w) + 2w
First you must distribute the 2 to the numbers inside the parentheses, which would be 4 and 2w...
26 = (2 * 4) + (2 * 2w) + 2w
26 = 8 + 4w + 2w
Now you must combine like terms. This means that first numbers with the same variables (w) must be combined...
26 = 8 + 4w + 2w
4w + 2w = 6w
26 = 8 + 6w
Now bring 8 to the left side by subtracting 8 to both sides (what you do on one side you must do to the other). Since 8 is being added on the right side, subtraction (the opposite of addition) will cancel it out (make it zero) from the right side and bring it over to the left side.
26 - 8 = 8 - 8 + 6w
18 = 0 + 6w
18 = 6w
To isolate w divide 6 to both sides
18 / 6 = 6w / 6
w = 3
We know that the width is 3 ft
Now you must find the length. To do this plug 3 where you see w in the equation:
length = 4 + 2w
l = 4 + 2(3)
l = 4 + 6
l = 10
We know that length is 10 ft
Letter B. is the correct answer
Hope this helped!
~Just a girl in love with Shawn Mendes
Since the "leading" runner in a race would be found in the first position, because he or she is in the lead, it means they are first, then I suppose I would find the "leading coefficient" in the first place in a polynomial as well.
