Duccio specialized in Byzantine
Answer:
As you probably know the perimeter of a rectangle is given by the formula 2l + 2w where the length and width are represented by the letters l and w .
In our case,
l = w + 5 ( since the problem states that the length is 5 more than the width)
70 = 2 (w+5) + 2w
70 = 2w + 10 + 2w
4w = 60
w = 15
l = 20
Our length is going to be 20 ft and our width 15 ft.
Explanation:
The perimeter is the sum of the two lengths and the two widths.
So if we let L = the length and W = the width, 2L + 2W = 70
If the length is 5 feet more than the width, then L = W + 5
Substitute W + 5 for L in the first equation--> 2(W + 5) + 2W = 70
2W + 10 + 2W = 70
4W + 10 = 70
4W = 60
W = 15
So L = 20
Plug these numbers back in to the question to make sure that they work.
Have fun.
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