Answer: The range of the data is (C) 
Step-by-step explanation: We are given to find the range of the following data:

<u>RANGE :</u> The range of a data is given by the difference between the larges and the smallest value in the data.
Arranging the given data in ascending order, we have

So, the largest value and the smallest values of the data are

Therefore, the range of the data is given by

Thus, option (C) is the correct option.