3 years ago

What is the first step for multiplying decimal numbers?

Mathematics

1 answer:

dimulka [17.4K]3 years ago

4 0

Read the question correctly

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The volume of a prism is 45 km3. What would change if the volume of the prism were measured in cubic meters?

givi [52]

The volume of the prism stays the same, but the number representing the volume increases because cubic meters converted to km is 1e-9

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3 years ago

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Cynthia was asked to subtract 0.223 from 0.54. Which of the following is the best estimate that cynthia can make to check her an

Zigmanuir [339]

I need help with this one too , can you guys please help us

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3 years ago

У + 2х = 7<br> у = 3х – 3<br> What is the answer to this

Neko [114]

I think the correct answer is ( 2, 3 )

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2 years ago

Use cylindrical coordinates. find the volume of the solid that lies within both the cylinder x2 y2 = 9 and the sphere x2 y2 z2 =

marissa [1.9K]

In Cartesian coordinates, the region is given by $-3\le x\le3$ , $-\sqrt{9-x^2}\le y\le\sqrt{9-x^2}$ , and $-\sqrt{16-x^2-y^2}\le z\le\sqrt{16-x^2-y^2}$ . Converting to cylindrical coordinates, using

$\begin{cases}\mathbf x(r,\theta,\zeta)=r\cos\theta\\\mathbf y(r,\theta,\zeta)=r\sin\theta\\\mathbf z(r,\theta,\zeta)=\zeta\end{cases}$

we get a Jacobian determinant of $r$ , and the region is given in cylindrical coordinates by $0\le\theta\le2\pi$ , $0\le r\le3$ , and $-\sqrt{16-r^2}\le z\le\sqrt{16-r^2}$ .

The volume is then

$\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=3}\int_{z=-\sqrt{16-r^2}}^{z=\sqrt{16-r^2}}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta=\dfrac{4(64-7\sqrt7)\pi}3$

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2 years ago

What is 1.2x=6? And can You show me the work?

harina [27]

You basiclly divide 6 and 1.2 and get your answer.

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3 years ago

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