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Aleks04 [339]
3 years ago
10

What is the square root of 7/8

Mathematics
1 answer:
ELEN [110]3 years ago
6 0

Answer:

√17/4

Step-by-step explanation:

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The 6 in 216 is in the ones place.
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Eleanor and Max used two rectangular pieces of plywood, placed end-to-end, to make a long rectangular stage for the school play.
irina1246 [14]

The area is the product of length and width.

.. area = length * width

.. 61 5/8 = (7 +7 1/2) * width

.. (61 5/8)/(14 1/2) = width = 4 1/4 . . . . feet

The plywood was 4 feet 3 inches wide.

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A calculator that works with fractions figures this nicely. By hand, you might compute it as

.. 61 5/8 = (8*61 +5)/8 = 493/8

.. 14 1/2 = (2*14 +1)/2 = 29/2

.. (61 5/8)/(14 1/2) = (493/8)/(29/2) = (493/8)*(2/29) = 493/(4*29) = 493/116

.. 493/116 = 4 +29/116 = 4 +29/(4*29) = 4 1/4

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A circular tablecloth has a diameter of 3 feet. Which measurement is closest to the area of the tablecloth in feet?
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The answer is b or c
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Explain how cell<br> division is<br> controlled.
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How many natural numbers less than 300 are neither multiples of 2 nor multiples of 3? show work please
Svet_ta [14]

Answer:100

Step-by-step explanation:

Suppose S is the set of number of first 300 natural number

S=\{1,2,3,4.......300\}

And A be the set of number divisible by 2

A=\{2,4,6.......300\}

so total element in A is \frac{300}{2}=150

Let B be the set containing the element divisible by 3

B=\{3,6,9......300\}

So element in B is \frac{300}{3}=100

But there are some element which is common in both A and B

so A\cap B={6,12,18.......300}

Element in A\cap B=\frac{300}{6}=50

and so number of elements which are less than 300 and neither divisible by 2  nor 3 is

=n(S)-n(A\cup B)

=300-(n(A)+n(B)-n(A\cap B))

=300-(150+100-50)

=300-200

=100

3 0
3 years ago
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