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3 years ago

What is the approximate area of a circle with a radius of 11 m?

Mathematics

2 answers:

Katarina [22]3 years ago

8 0

Answer:

380.13

Step-by-step explanation:

area= (pi)x(r^2)

pi times r squared

Tamiku [17]3 years ago

4 0

Answer:

380 m^2 to the nearest whole number.

Step-by-step explanation:

That would be 3.14 * 11^2

= 380 .

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tom's baseball team wins 5 out every 12 games they play. If the team played 36 games, how many games did Tom's team win

atroni [7]

Answer:

15 games

Step-by-step explanation:

12X3=36 5X3=15

6 0

3 years ago

Based on a poll conducted by the Centers for Disease Control, 862 of 1013 randomly selected adults said that they always wear se

ivolga24 [154]

The confidence interval is 0.028, 0.872

<h3>Given </h3>

862 of 1013 randomly selected adults wear seat belts.

The 95% confidence interval for the proportion of adults who always wear seat belts.

<h3>What is confidence interval?</h3>

A Confidence Interval is defined as a range of values we are sure our true value lies within it.

<h3>What is 95% confidence interval?</h3>

A 95% confidence interval is defined as that if we take 100 different samples and compute a 95% confidence interval for each sample, then approximately 95 of the 100 confidence intervals will contain the true mean value.

= 862/1013 = 0.85

At a 95% confidence interval ,the critical value is $z_{0.025} = 1.96$

The 95% confidence interval for proportion is

$\widehat p +/- z0.025 * sqrt(\widehat p * (1 - \widehat p)/n)$

$= 0.85 +/- 1.96 * sqrt(0.85 * (1 - 0.85)/1013)$

$= 0.85 +/- 0.022$

= 0.028, 0.872

The sample should use at least 10 successes and 10 failures.

$n * \widehat p = 1013 * 0.85 = 861 > 10$

$n * (1 - \widehat p) = 1013 * 0.15 = 152 > 10$

As the sample size is larger, we can use an approximate formula for the standard error.

Learn more on Confidence intervals here:

brainly.com/question/8961482

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3 0

2 years ago

the population of a town today is 50000 people if the population decreased by 5% a year what will the towns population be in 10

kramer

The population of the town in 10 years would be 29,937.

5 0

3 years ago

Y-intercept for the graph or 3x-5y=6

mr Goodwill [35]

The answer is B. -6/5

4 0

3 years ago

Read 2 more answers

The estimated value of the integral from 0 to 2 of x cubed dx , using the trapezoidal rule with 4 trapezoids is

bulgar [2K]

The integral is approximated by the sum,

$\displaystyle\int_0^2f(x)\,\mathrm dx\approx\sum_{n=0}^4\frac12\times\frac{f(x_n)+f(x_{n+1})}2=\frac14\sum_{n=0}^3(f(x_n)+f(x_{n+1}))$

where $f(x)=x^3$ and $x_n=\dfrac12n$ , giving you

$\displaystyle\frac14\sum_{n=0}^3\bigg(\left(\frac n2\right)^3+\left(\frac{n+1}2\right)^3\bigg)$
$\displaystyle\frac1{32}\sum_{n=0}^3(n^3+(n+1)^3)$
$\displaystyle\frac1{32}\sum_{n=0}^3(2n^3+3n^2+3n+1)$

Faulhaber's formulas make short work of computing the sum. You have

$\displaystyle\sum_{n=0}^k1=k+1$
$\displaystyle\sum_{n=0}^kn=\frac{k(k+1)}2$
$\displaystyle\sum_{n=0}^kn^2=\frac{k(k+1)(2k+1)}6$
$\displaystyle\sum_{n=0}^kn^3=\frac{k^2(k+1)^2}4$

which gives

$\displaystyle\frac1{16}\sum_{n=0}^3n^3+\frac3{32}\sum_{n=0}^3n^2+\frac3{32}\sum_{n=0}^3n+\frac1{32}\sum_{n=0}^31$
$\displaystyle\frac{36}{16}+\frac{42}{32}+\frac{18}{32}+\frac4{32}$
$\implies\displaystyle\int_0^2x^3\,\mathrm dx\approx\frac{17}4=4.25$

4 0

3 years ago