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Temka [501]
4 years ago
15

Given that the variables x and y have already been declared and assigned values, write an expression that evaluates to true if x

is non-negative and y is negative.
Computers and Technology
1 answer:
Eduardwww [97]4 years ago
3 0

Answer:

The expression to this question can be defined as follows:

Expression:

(x >= 0 && y<0) //check condition using AND operator

Explanation:

In the given question it is defined that x and y are an integer variable that holds some value, in which it defines a condition that checks the value of variable x is positive, and the value of y is negative.

  • To check positive value a condition is used, that checks x greater than equal to 0, and to check negative value, it uses condition, that is y is less than 0.
  • In the above condition, the AND operator is used, which executes when both conditions are true.
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Data ____________ refers to any technique that recodes the data in a file so that it contains fewer bits.​
Darina [25.2K]

Hi!

Data Compression refers to any technique that recodes the data in a file to contain fewer bits.

Hope this helps!

4 0
4 years ago
In order to "print" the data in an object, the class should override the _____ method.
Olegator [25]

Answer:

toString is right Answer

Explanation:

If you want to represent any object as a string, toString() method comes into existence.  

The toString() method returns the string representation of the object.

If you print any object, java compiler internally invokes the toString() method on the object. So overriding the toString() method, returns the desired output, it can be the state of an object etc. depends on your implementation.

7 0
4 years ago
TCP has a 32-bit sequence number field and 16-bit advertised window field. Assume that RTT is 512 (2 9 ) ms, transmission speed
Natalka [10]

Answer:

See explaination

Explanation:

Usable sequence numbers = 2^31

Transmission speed = 2^30 bps

(a)Wrap around time = (2^31 * 8 * 1)/(2^30) = 16 seconds

(b)segment size = 16 Bytes

Wrap around time = (2^31 * 8 * 16)/(2^30) = 256 seconds

(c)if we use large segment size ,which increases size of MTU in data link layer .Maximum transmission unit is the maximum size of a packet or frame that can flow across the network, without being fragmented,which lead to overhead of fragmentation at network layer.

(d)Maximum network throughput equals the TCP window size divided by the round-trip time of communications data packets.

Round trip time = 2^9 ms

window size = 2^16

Throughput = (2^16)/(2^9) = 2^7 KBps = 128 KBps = 1Mbps

6 0
3 years ago
A mobile base station (BS) in an urban environment has a power measurement of 15 µW at 175 m. If the propagation follows an inve
PIT_PIT [208]

Answer:

The reasonable power will be "0.234 μW".

Explanation:

The given values are:

P = 15 μW

d = 175 m

As we know,

Propagation follows inverse cube power law, then

∴  Power \ \alpha \ \frac{1}{d^3}

⇒ Power=\frac{K}{d^3}

On substituting the estimated values, we get

⇒  15\times 10^{-6}=\frac{K}{(173)^3}

⇒  K=15\times (175)^3\times 10^{-6}

Now,

"P" at 0.7 km or 700 m from BS will be:

⇒  P=\frac{K}{d^3}

⇒  P=\frac{15\times (175)^3\times 10^{-6}}{(700)^3}

⇒  P=0.234 \ \mu W

6 0
3 years ago
Draw directed graphs representing relations of the following types.
mixas84 [53]

Answer:

The first graph in the picture describes a relation that is (a) Reflexive, transitive, and anti-symmetric.

Because a, b, c, d all are related to itself, so reflexive.

where (a, b) and (b, d) are in the relation, (a,d) is in the relation,    

for (c,a) and (a,b) there is (c,b).

so it's transitive.

for all a,b in the relation, (a,b) there is no (b,a) with a ≠b.

The second graph in the picture describes a relation that is (b) Reflexive, transitive, and neither symmetric nor anti-symmetric.

Because a, b, c, d all are related to itself, so reflexive.

where (a, b) and (b, a) are in the relation, (a,a) is in the relation,                                                    

where (c, d) and (d, d) are in the relation, (c,d) is in the relation,                                                    

so it's transitive.

Because, (a,b) and (b.a) are there, but for (c,d) there is no (d,c) in relation.

So, the relation is not symmetric.

(a,b) and (b,a) is in relation but, a≠b, so not anti symmetric.

Explanation:

For all a in a set,  if (a,a) in a relation then the relation is reflexive.

For all (a,b) in relation R, if (b,a) is also in R, then R is symmetric.

For all (a,b), (b,c) in relation R, if (a,c) is also in R, then R is transitive.

For all (a,b), (b,a) in R, a = b,  then R is an anti- symmetric relation.

3 0
3 years ago
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