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3 years ago

279 for 9 tickets how do I solve this?

Mathematics

1 answer:

8090 [49]3 years ago

5 0

You have to divide and the answer will be 31

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Need help on this guys

MakcuM [25]

Answer:

pretty sure its 5

Step-by-step explanation:

8 0

2 years ago

Maria bought a blouse on sale for 30% off. The sale price was $28.76. What was the original price? Write an equation to model th

Snowcat [4.5K]

Answer:

The equation is sale price=p and the original price is $41.09.

.70

Step-by-step explanation:

sale price= (1-.30)p

sale price=.70p

.70 .70

sale price=p

.70

28.76=p

.70

$41.09=p

7 0

3 years ago

I now have another question to ask.

marissa [1.9K]

Answer:

23.6 ft

Step-by-step explanation:

Sketch a right triangle representing this situation. The length of the hypotenuse is 26 ft and the angle of elevation from ground to top of ladder is 65°. The "opposite side" is the reach of the ladder, which we'll call x.

Then:

opp

sin 65° = ----------
26 ft

or (26 ft)(sin 65°) = opp side = height off the ground of top of ladder.

Evaluating this, we get:

(26 ft)(0.906) = 23.56 ft, or, rounded off, 23.6 ft

The ladder reaches 23.6 ft up the side of the building.

8 0

3 years ago

Use multiplication or division of power series to find the first three nonzero terms in the Maclaurin series for the function. (

Mrrafil [7]

Answer:

So, the first three nonzero terms in the Maclaurin series are:

$6, \, 27x^2, \, \frac{405x^4}{4}.$

Step-by-step explanation:

From exercise we have the next function y = 6 sec(3x).

We know that Maclaurin series for the function sec x, have the following form:

$\sec x=1+\frac{x^2}{2}+\frac{5x^4}{24}+...$

So, for the given function y = 6 sec(3x), we get:

$y = 6 \sec(3x)=6+27x^2+\frac{405x^4}{4}+...$

So, the first three nonzero terms in the Maclaurin series are:

$6, \, 27x^2, \, \frac{405x^4}{4}.$

6 0

2 years ago

(a) Find a 90% confidence interval for the population mean price (per 100 pounds) that farmers in this region get for their wate

Anon25 [30]

Answer:

The margin of error (E) $=0.49$

Step-by-step explanation:

Given,

mean $\bar{x}=6.88$

standard deviation $\sigma=1.90$

sample size $n=41$

$90\% \quad \text{confidence interval}$

Critical value $=\frac{z_\alpha}{2}\quad \quad\quad[\because\;\alpha=1-\text{confidence interval}]$

$=1-0.90$

$\Rightarrow \alpha=0.1$

Critical value $=\frac{z_{0.1}}{2}$

$=z_{0.05}$

$=1.645$

The margin of error (E) $=\frac{z_\alpha}{2} \times\frac{\sigma}{\sqrt{n} }$

$=1.645\times\frac{1.90}{\sqrt{41} }$

$=0.49$

Hence, The margin of error (E) $=0.49$

Complete question is attached in below.

7 0

3 years ago