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2 years ago

What would be another way to write -8n-7

Mathematics

1 answer:

AysviL [449]2 years ago

6 0

Answer:

-7 - 8n

Step-by-step explanation:

Another way would be to rearrange the terms = -7 - 8n

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HELP. ASAP. EASY MUTIPLE CHOICE QUESTIONS.

Alina [70]

Answer:

C 44.59

Step-by-step explanation:

The first two shirts are full price

2*49.96 = 99.92

The third shirt is 50% off. That means it is 50% of the original price

.5*49.96 = 24.98

The total cost before tax is

99.92+24.98 =124.90

tax = cost * tax rate

tax = 124.90*.071

tax=8.87

Add this to the cost

final cost = 124.90+8.87

=133.77

We want to find the mean cost (average cost)

Take the total cost and divide by the number of shirts

133.77/3 =44.59

5 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=7%20-%208%20%5Cdiv%204%28%20%7B3%7D%5E%7B2%7D%20%20-%201%29" id="TexFormula1" title="7 - 8 \di

Aleonysh [2.5K]

Use PEMDAS

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

$7-8\div4\cdot(3^2-1)=7-2\cdot(9-1)=7-2\cdot8=7-16=-9$

4 0

3 years ago

A shipping company damaged 15 packages. Each package was valued at $175.50. Which expression represents this situation?

Allushta [10]

Answer: A

Step-by-step explanation:

15 packages damaged. Cost is -175.50 this is a loss. So 15x(-175.50)

3 0

3 years ago

Why is #2 the expression ln(2e)^3x equivalent to choice B?

motikmotik

Hello:
ln(2e^3x) =ln2+lne^3x
 =ln2 +3xlne
= ln2+3x .....lne=1
choice B

8 0

2 years ago

find the area of the trapezium whose parallel sides are 25 cm and 13 cm The Other sides of a Trapezium are 15 cm and 15 CM

Snezhnost [94]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Given - A trapezium ABCD with non parallel sides of measure 15 cm each ! along , the parallel sides are of measure 13 cm and 25 cm

To find - Area of trapezium

Refer the figure attached ~

In the given figure ,

AB = 25 cm

BC = AD = 15 cm

CD = 13 cm

Construction -

$draw \: CE \: \parallel \: AD \: \\ and \: CD \: \perp \: AE$

Now , we can clearly see that AECD is a parallelogram !

$\therefore$ AE = CD = 13 cm

Now ,

$AB = AE + BE \\\implies \: BE =AB - AE \\ \implies \: BE = 25 - 13 \\ \implies \: BE = 12 \: cm$

Now , In ∆ BCE ,

$semi \: perimeter \: (s) = \frac{15 + 15 + 12}{2} \\ \\ \implies \: s = \frac{42}{2} = 21 \: cm$

Now , by Heron's formula

$area \: of \: \triangle \: BCE = \sqrt{s(s - a)(s - b)(s - c)} \\ \implies \sqrt{21(21 - 15)(21 - 15)(21 - 12)} \\ \implies \: 21 \times 6 \times 6 \times 9 \\ \implies \: 12 \sqrt{21} \: cm {}^{2}$

Also ,

$area \: of \: \triangle \: = \frac{1}{2} \times base \times height \\ \\\implies 18 \sqrt{21} = \: \frac{1}{\cancel2} \times \cancel12 \times height \\ \\ \implies \: 18 \sqrt{21} = 6 \times height \\ \\ \implies \: height = \frac{\cancel{18} \sqrt{21} }{ \cancel 6} \\ \\ \implies \: height = 3 \sqrt{21} \: cm {}^{2}$

Since we've obtained the height now , we can easily find out the area of trapezium !

$Area \: of \: trapezium = \frac{1}{2} \times(sum \: of \:parallel \: sides) \times height \\ \\ \implies \: \frac{1}{2} \times (25 + 13) \times 3 \sqrt{21} \\ \\ \implies \: \frac{1}{\cancel2} \times \cancel{38 }\times 3 \sqrt{21} \\ \\ \implies \: 19 \times 3 \sqrt{21} \: cm {}^{2} \\ \\ \implies \: 57 \sqrt{21} \: cm {}^{2}$

hope helpful :D

6 0

1 year ago