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3 years ago

What is another way to write 4 hundreds

Mathematics

2 answers:

Temka [501]3 years ago

7 0

40 tens is another way of writing 4 hundreds because 40 tens would give you 400 and 4 hundreds also give you 400.

Anna35 [415]3 years ago

5 0

400 = four hundred
0.04= four hundredths

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G(t)=(t+1) ^2-20.25 what are the zeros of the function

Vinil7 [7]

Step-by-step explanation:

g(t) = (t + 1)² − 20.25

0 = (t + 1)² − 20.25

20.25 = (t + 1)²

±4.5 = t + 1

t = -1 ± 4.5

t = -5.5 or 3.5

The zeros are (-5.5, 0) and (3.5, 0).

5 0

3 years ago

The probability of being a universal donor is 6% (O-negative-blood type). Suppose that 6 people come to a blood drive.

Rufina [12.5K]

Answer:

babala

Step-by-step explanation:

The probability of being a universal donor is 6% (O-negative-blood type). Suppose that 6 people come to a blood drive.

a) What are the mean and standard deviation of the number of universal donors among the 6 people?

b) What is the probability that there are exactly three universal donors?

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2 years ago

11-24! Please help! Middle school homework

Dimas [21]

11-24= -35
Hope I helped !!

7 0

3 years ago

Your parents have said that you can invite four friends to a game. The price of the tickets is listed below. If you purchase you

nasty-shy [4]

Answer:

5 tickets after may 30th would be $135.

5 tickets before may 30th would be $121.50

Step-by-step explanation:

If you buy the 4 tickets + the one ticket you would get $135 for after may 30th then multiply that by .1 to get 121.5 for before may 30th with the 10% off.

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3 years ago

A large tank is filled to capacity with 600 gallons of pure water. brine containing 4 pounds of salt per gallon is pumped into t

nignag [31]

If $A(t)$ is the amount of salt in the tank at time $t$ , then the rate at which the amount of salt in the tank changes is given by

$\dfrac{\mathrm dA(t)}{\mathrm dt}=\dfrac{4\text{ lbs}}{1\text{ gal}}\dfrac{6\text{ gal}}{1\text{ min}}-\dfrac{A(t)\text{ lbs}}{600\text{ gal}}\dfrac{6\text{ gal}}{1\text{ min}}$
$\dfrac{\mathrm dA}{\mathrm dt}=24\dfrac{\text{lb}}{\text{min}}-\dfrac{A(t)}{100}\dfrac{\text{lb}}{\text{min}}$

Let's drop the units for now. We have

$\dfrac{\mathrm dA(t)}{\mathrm dt}+\dfrac{A(t)}{100}=24$
$e^{t/100}\dfrac{\mathrm dA(t)}{\mathrm dt}+e^{t/100}\dfrac{A(t)}{100}=24e^{t/100}$
$\dfrac{\mathrm d}{\mathrm dt}\left[e^{t/100}A(t)\right]=24e^{t/100}$
$e^{t/100}A(t)=\displaystyle24\int e^{t/100}\,\mathrm dt$
$e^{t/100}A(t)=2400e^{t/100}+C$
$A(t)=2400+Ce^{-t/100}$

We're given that the water is pure at the start, so $A(0)=0$ , giving

$A(0)=0=2400+Ce^{-0/100}\implies C=-2400$

So the amount of salt in the tank (in lbs) at time $t$ is

$A(t)=2400\left(1-e^{-t/100}\right)$

4 0

2 years ago