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ArbitrLikvidat [17]
3 years ago
6

Two boxers bump heads in a boxing match. The referee will check for a concussion on one of the boxers. Consider a null hypothesi

s, , that the boxer does not have a concussion, and an alternative hypothesis, , that the boxer did get a concussion. The referee has two possible decisions: stop the match due to injury (reject the null hypothesis) or allow the match to continue (do not reject the null hypothesis). If the referee makes a Type I error, what happened?
A. He allowed the match to continue, and the boxer did not have a concussion.
B. He stopped the match due to injury, but the boxer did not have a concussion.
C. He stopped the match due to injury, and the boxer did have a concussion.
D. He allowed the match to continue, but the boxer did have a concussion.
Mathematics
1 answer:
Natalka [10]3 years ago
4 0
B,hope this helped!
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HELP
RUDIKE [14]

Answer:

Step-by-step explanation:

a₂ - a₁ = 20 - 4 = 16

a₃ - a₂ = 100 - 16 = 84

Since a₂ - a₁ ≠ a₃ - a₂, the sequence is not arithmetic.

a₂/a₁ = 20/4 = 5

a₃/a₂ = 100/20 = 5

Since a₂/a₁ = a₃/a₂ = 5, the sequence is geometric with a common ratio of 5.

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2 years ago
You drive 200 km west, then 100 km northeast, and then 100 km at 30.0° south of east. after an additional displacement, you arri
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The direction is your final destination
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3 years ago
Please help!<br>"solving proportions" is what needs done<br>please show all work clearly!​
Oksana_A [137]

23) x = \frac{-60}{9} = -6.666.

24) x = \frac{-12}{7} = -1.7142.

25) x = \frac{-37}{5} = -7.4.

Step-by-step explanation:

Step 1; For \frac{x+6}{3} = \frac{x+4}{12}, we cross multiply the denominators and get,

3 × (x + 4) = 12 × (x + 6),

3x + 12 = 12x + 72.

We take all the x terms to the LHS and keep the constants on the RHS.

3x - 12x = 72 - 12,

-9x = 60, x = \frac{-60}{9} = -6.6666.

Step 2; For \frac{-5}{x-4} = \frac{9}{x+12}, we cross multiply the denominators and get,

-5 × (x + 12) = 9 × (x - 4),

-5x - 60 = 9x - 36.

We take all the x terms to the LHS and keep the constants on the RHS.

-5x - 9x = -36 + 60,

-14x = 24, x = \frac{-24}{14} = -1.7142.

Step 3; For \frac{6}{11} = \frac{x-1}{x-8}, we cross multiply the denominators and get,

6 × (x - 8) = 11 × (x - 1),

6x - 48 = 11x - 11.

We take all the x terms to the LHS and keep the constants on the RHS.

6x - 11x = -11 + 48,

-5x = 37, x = \frac{-37}{5} = -7.4.

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