onji has $5.25 in nickels and dimes.The coin value can be modeled by the equation 0.10d + 0.05n = 5.25, where d represents the n umber of dimes and n represents the number of nickels. If Sonji has 21 dimes, how many nickels does she have
1 answer:
This is how you solve this problem: .10d + .05n = 5.25 (plug in the number of dimes we have) (21 x .1) + .05n = 5.25 (multiply number of dimes x value of the dime) 2.10 + .05n = 5.25 (subtract 2.10 from both sides) .05n = 3.15 (divide both sides by .05 to get the number of nickels)n = 63 nickels Hope this helps!
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