Answer:
it is organism the third one
The pH of the weak acid is 6.93.
Given,
K= 1.15 *
c=0.102
[H]= K*c= 1.15 * * 0.102= 0.1173 *
p[H]= -log[H]= 6.93
<h3>Weak acid</h3>
A weak acid is one that partially separates into its ions in water or an aqueous solution. A strong acid, on the other hand, completely splits into its ions in water. The conjugate base of a weak acid is also a weak base, and vice versa for the conjugate acid of a weak base. Weak acids have a higher pH than strong acids at the same concentration. Simple arrows pointing left to right are used to represent the reaction of a strong acid ionising in water. On the other hand, a weak acid ionising in water has a double arrow reaction arrow, indicating that both the forward and reverse reactions take place at equilibrium.
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If 28.0 grams of a gas occupies 22.4 liters at STP, the gas could be carbon monoxide, CO
<h3>Ideal gas </h3>
We understood from the ideal gas equation that 1 mole of any gas occupies 22.4 liters at standard temperature and pressure (STP)
<h3>How to determine the identity of the gas</h3>
To determine the identity of the gas, we shall determine the mass of 1 mole of each gas. This can be obtained as
For C₂H₂
1 mole of C₂H₂ = (12×2) + (2×1) = 26 g
For C₂H₆
1 mole of C₂H₆ = (12×2) + (6×1) = 30 g
For CO₂
1 mole of CO₂ = 12 + (16×2) = 44 g
For CO
I mole of CO = 12 + 16 = 28 g
From the above illustrations, we can see that 1 mole of CO is equivalent to 28 g.
Thus, the correct answer to the question is CO
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Answer:
36.2 K
Explanation:
Step 1: Given data
- Initial pressure of the gas (P₁): 8.6 atm
- Initial temperature of the gas (T₁): 38°C
- Final pressure of the gas (P₂): 1.0 atm (standard pressure)
- Final temperature of the gas (T₂): ?
Step 2: Convert T₁ to Kelvin
We will use the following expression.
K = °C +273.15
K = 38 °C +273.15 = 311 K
Step 3: Calculate T₂
We will use Gay Lussac's law.
P₁/T₁ = P₂/T₂
T₂ = P₂ × T₁/P₁
T₂ = 1.0 atm × 311 K/8.6 atm = 36.2 K
I'm quite sure the 'F' is a mistake, and the word is MIXTURE.
