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lyudmila [28]
4 years ago
5

Propane (C3 H8 (g), Delta.Hf = –103.8 kJ/mol) reacts with oxygen to produce carbon dioxide (CO2 , Delta.Hf = –393.5 kJ/mol ) and

water (H2 O, Delta.Hf = –241.82 kJ/mol) according to the equation below. Upper C subscript 3 upper H subscript 8 (g) plus 5 upper O subscript 2 (g) right arrow 3 upper C upper O subscript 2 (g) plus 4 upper H subscript 2 upper O (g). What is the enthalpy of combustion (per mole) of C3 H8 (g)? Use Delta H r x n equals the sum of delta H f of all the products minus the sum of delta H f of all the reactants.
Chemistry
2 answers:
MrRissso [65]4 years ago
6 0

Answer:

a

Explanation:

becasue i said so. boom roasted.

xeze [42]4 years ago
4 0

Answer:

-2,044.0 kJ/mol

Explanation:

<em> I just did the test on edg</em>

<em />

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Explanation:

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Plug and chug:

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Calculate the initial rate for the formation of c at 25 ∘c, if [a]=0.50m and [b]=0.075m
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The rate of formation of a product depends on the the concentrations of the reactants in a variable way.

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Where the symbol [ ] is the concentration of each compound.

Then, plus the concentrations of compounds A and B you need k, m and n.

Normally you run controled trials in lab which permit to calculate k, m and n .

Here the data obtained in the lab are:

<span>Trial      [A]      [B]         Rate </span><span>
<span>            (M)     (M)          (M/s) </span>
<span>1         0.50    0.010      3.0×10−3 </span>
<span>2         0.50    0.020       6.0×10−3 </span>
<span>3         1.00 0  .010       1.2×10−2</span></span>


Given that for trials 1 and 2 [A] is the same you can use those values to find n, in this way

rate 1 = 3.0 * 10^ -3 = k [A1]^m * [B1]^n

rate 2 = 6.0*10^-3 = k [A2]^m * [B2]^n

divide rate / rate 1 => 2 = [B1]^n / [B2]^n

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2 = 2^n => n = 1

 
Given that for data 1 and 3 [B] is the same, you use those data to find m

rate 3 / rate 1 = 12 / 3.0   = (1.0)^m / (0.5)^m =>

4 = 2^m => m = 2

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k = 3.0*10^-3 m/s / 0.025 m^3 = 0.12 m^-2 s^-1

Now that you have k, m and n you can use the formula of the rate with the concentrations given

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Answer: 4.5 * 10^-3 m/s
8 0
3 years ago
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Answer:

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