Answer:
pH is 7.60
Explanation:
Let's think the equations:
HClO + H₂O ⇄ ClO⁻ + H₃O⁺
As every weak acid, we make an equilbrium
The salt is dissociated in solution
NaClO → Na⁺ + ClO⁻
HClO + H₂O ⇄ ClO⁻ + H₃O⁺
Initially 0.3m 0.35m
We have the moles of acid, and the moles of conjugate base.
Reacts x X X
Some amount has reacted, so I obtained (in equilibrium) the moles of base + that amount, and the same amount for H₃O⁺ (ratio is 1:1)
HClO + H₂O ⇄ ClO⁻ + H₃O⁺
0.3 - x 0.35 + x x
Let's make the expression for Ka
Ka = [ClO⁻] . [H₃O⁺] / [HClO]
(we don't add water, because it is included in Ka)
2.9x10⁻⁸ = (0.35+x).x / (0.3-x)
Ka is in order of 10⁻⁸, I can assume that 0.3-x is 0.3 and 0.35 +x =0.3
2.9x10⁻⁸ = (0.35)x / (0.3)
(2.9x10⁻⁸ . 0.3) /0.35 = x
2.48x10⁻⁸ = x
This is [H₃O⁺]
For pH = - log [H₃O⁺]
pH = 7.60
1.A two face mixture is a type of mixture in which the components of the mixture are in different states of matter. A good example of a two face mixture is carbonated soft drink. Carbonated soft drink is a mixture of carbon dioxide [which is a gas] and water [which is a liquid]. Another example of a two face mixture is the the mixture of iodine and sodium solution.
2. To separate the mixture of iodine and sodium solution the best separation method to use is sublimation.
Sublimation process is used to separate mixtures in which one of the component of the mixture can translate from the solid state to the gaseous state without passing through the liquid state. An example of a solid which can sublime is iodine.
The sublimation process involves heating the mixture. On heating, the sublime solid will turn to vapour and escape from the mixture leaving behind the other component. The sublime component will be regained when it cools down.
It would keep traveling westward
Answer:
a) Theoretical yield of ethanol = 34.778 g
b) % yield of ethanol = 37.38%
Explanation:
a)
C6H12O6 → 2 C2H5OH + 2 CO2
Molar mass of glucose = 180.156 g/mol
Molar mass of ethanol = 46.07 g/mol
amount of glucose taken = 68.0 g
No. of mole = Amount of substance in g/Molar mass
[text]No. of mole = \frac{68.0\;}{180.156\; g/mol} =0.37745 mol[\text]
from reaction stoichiometry, one mole of glucose fermented two form 2 mole of ethanol.
therefore, 0.37745 mol of glucose will form 0.37745*2 moles of ethanol.
No. of moles of ethanol formed = 0.7549 mol
theoretical yield of ethanol = 0.7549 x 46.07 = 34.778 g
b)
Actual yield = 13.0 g
Theoretical yield = 34.778 g
= 37.38%
