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sdas [7]
3 years ago
10

Whats the work for 0>3x-3-6

Mathematics
1 answer:
erik [133]3 years ago
7 0

Hi Scotti


0>3x-3-6

0>3x-9

Now flip

3x-9<0

We need to add 9 to both sides

3x-9+9<0+9

3x<9

Divide both sides by 3 so we can find the value for x

3x/3<9/3

x<3


I hope that's help :)

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C. Find a parametrization for the line segment with endpoints (-1, 3) and (3, -2).
wel

Answer:

x(t) = -1 + 4t

y (t) = 3 - 5t

Step-by-step explanation:

The end points of the line segment are (-1, 3) and (3, -2).

Let a = (-1,3) and b = (3,-2)

Now, find the value of (b-a)

(b-a) = ((3+1), (-2-3))

b-a = (4, -5)

Therefore, the parametrization of the given line segment is

r(t) = a + (b-a)t

r(t) = (-1,3) +(4,-5)t

r(t) = (-1+4t, 3-5t)

We can rewrite this as

x(t) = -1 + 4t

y (t) = 3 - 5t

3 0
3 years ago
13) -3x - 4y = 8<br>-4x - 3y=6​
Dvinal [7]

Answer:

x = 0, y = -2

Step-by-step explanation:

-3x - 4y = 8  (1)

-4x - 3y=6​ (2)

Multiply (1) by -4 and (2) by -3, we have:

12x + 16y = - 32  (3)

12x + 9y= -18​ (4)

Subtract (4) from (3), we have:

(12x + 16y) - (12x + 9y) = - 32  - (-18)

<=> 7y = - 14

=> y = - 2

Replace y with - 2 in (3), we have x = 0

6 0
4 years ago
How do I work this out?
NeTakaya
Multiply them all together
8 0
3 years ago
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